The pressure at the point on the roof where the speed is 60mph is 14.66 psi
<u>Explanation:</u>
The question follows Bernoulli's equation
P1 + 1/2 ρ V1² = P2 + 1/2 ρ V2²
V1 = 40 X 5280 / 3600 = 58.7 ft/s
V2 = 60 X 5280 / 3600 = 88 ft/s
P2 = P1 + 1/2 ( 0.00238 ) [(58.7)² - (88)²]
P2 - P1 = -5.12lb/ft²
The negative pressure created tends to lift the roof.
We know,
P1 = 14.7 psi = 2116.8 lb/ft²
P2 = 2116.8 - 5.12 lb/ft²
P2 = 2111.68 lb/ft²
P2 = 14.66 psi
Therefore, the pressure at the point on the roof where the speed is 60mph is 14.66 psi
Answer:
pon una imagen, lo busco y le pregunto :D
Explanation:
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Answer:
Explanation:
Force on Q₃ due to charge Q₁
= 9 x 10⁹x 4 x 10⁻⁹ x1 x 10⁻⁹ / 5²
= 1.44 x 10⁻⁹ N
Force due to Q₂ will also be 1.44 x 10⁻⁹ N
component of these forces along x axis
-= 2 x 1.44 x 10⁻⁹ cosθ
= 2.88 x 10⁻⁹ x 4/5
= 2.30x10⁻⁹ N along x axis.
The y-component will calcel out.
b ) In this case , Q₁ will repel and Q₂ will attract.
In this case Q₁ will repel and Q₂ will attract. Component along y - axis will be same as earlier one or 2.30x10⁻⁹ N . Component along x axis will cancel out.
c ) Electric field in case 1 and case 2 will be
= 2.30x10⁻⁹ / 1 x 10⁻⁹
= 2.3 N / C , because field is force per unit charge. The sane field will be in case 2 .
