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otez555 [7]
3 years ago
5

List at least three steps required before becoming a certified civil engineer.

Engineering
2 answers:
Elden [556K]3 years ago
5 0

Answer:

Step 1: Prepare While Still in High School. ...

Step 2: Earn a Bachelor of Science in Civil Engineering. ...

Step 3: Get Professional Experience

Explanation:

brainliest

Vlad [161]3 years ago
5 0

Answer:

The correct answer will list three steps from among the following: obtaining a bachelor’s degree, serving an internship, taking physics and mathematics classes, and obtaining a professional engineer’s license.

Explanation:

<em>IM A DIFFERENT BREEED!</em>

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Answer:

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3 years ago
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scrapers are used to haul dirt from a borrow pit to the cap of a landfill. the estimated cycle time for the scrapers is 9.5 minu
ladessa [460]
Answer is: 12.8 because when you multiply it by the 2nd power of 8 then the scraper equals to be 12.8 in height and that’s how much each scraper requires to operate :)
7 0
3 years ago
A rigid tank contains an ideal gas at 40°C that is being stirred by a paddle wheel. The paddle wheel does 240 kJ of work on the
Sergeu [11.5K]

To solve the problem it is necessary to consider the concepts and formulas related to the change of ideal gas entropy.

By definition the entropy change would be defined as

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{P_2}{P_1})

Using the Boyle equation we have

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{v_1T_2}{v_2T_1})

Where,

C_p = Specific heat at constant pressure

T_1= Initial temperature of gas

T_2= Final temprature of gas

R = Universal gas constant

v_1= Initial specific Volume of gas

v_2= Final specific volume of gas

According to the statement, it is an isothermal process and the tank is therefore rigid

T_1 = T_2, v_2=v_1

The equation would turn out as

\Delta S = C_p ln1-ln1

<em>Therefore the entropy change of the ideal gas is 0</em>

Into the surroundings we have that

\Delta S = \frac{Q}{T}

Where,

Q = Heat Exchange

T = Temperature in the surrounding

Replacing with our values we have that

\Delta S = \frac{230kJ}{(30+273)K}

\Delta S = 0.76 kJ/K

<em>Therefore the increase of entropy into the surroundings is 0.76kJ/K</em>

8 0
3 years ago
The difference between a thermocouple and a thermistor is the A. technology inside. B. thermocouple measures temperatures at the
Zepler [3.9K]

Answer: B. thermocouple measures temperatures at the tip and the thermistor at the dimple.

Explanation:

A thermistor is a temperature-sensitive resistor, whilst a thermocouple generates a voltage proportional to the temperature. Thermocouples can work at much higher temperatures than thermistors. They are commonly used for temperature control in heating systems.

8 0
3 years ago
Describe how to mix and apply body filler?
malfutka [58]
This is all you need to mix body filler.
Start with a golf-ball size glob of filler.
Squeeze a ribbon of hardner across the filler.
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Mix until overall color is even.
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