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Aleksandr-060686 [28]
1 year ago
8

Solve - 3x^2 + 2x + 4 = -x- 3 by writing a linear-quadratic system and solving using the intersection feature of a graphing calc

ulator,The graphing calculator shows the curve and line intersect at
Mathematics
1 answer:
Butoxors [25]1 year ago
5 0

Given,

-3x^2+2x+4=-x-3-3x^2+3x+7=0

Solving the above equation,

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Here, a=-3, b=3 and c=7

Therefore,

x=\frac{-3\pm\sqrt[]{9+84}}{-6}x=\frac{-3+\sqrt[]{93}}{-6}\text{ or }x=\frac{-3-\sqrt[]{93}}{-6}\text{ }

Therefore,

x=-1.11\text{ or }x=2.11

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The equation of a parabola is y=x2+6x+9. Write the equation in vertex form.
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Answer:

Step-by-step explanation:

Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

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Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

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The reason we do this is to create a perfect square binomial on the left:

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See below.

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