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3 years ago

15

I would love the help, 13 points !!!!!

2 answers:

lorasvet [3.4K]3 years ago

7 0

Answer:

<em><u>S</u></em><em><u>E</u></em><em><u>E</u></em><em><u> </u></em><em><u>I</u></em><em><u>M</u></em><em><u>A</u></em><em><u>G</u></em><em><u>E</u></em><em><u> </u></em><em><u>F</u></em><em><u>I</u></em><em><u>R</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u>R</u></em><em><u> </u></em><em><u>A</u></em><em><u>N</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>R</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

Luba_88 [7]3 years ago

4 0

Answer:

know I love you too baby I love

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Show that the transformation T defined by<br>T(x1, x2) = (2x1 - 3x2, X1+4, 5x2) is not linear.<br>

erastovalidia [21]

Let <em>u</em> = (1, 0) and <em>v</em> = (0, 1). Then

<em>T</em> (<em>u</em>) = (2*1 - 3*0, 1 + 4, 5*0) = (2, 5, 0)

<em>T</em> (<em>v</em>) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)

=> <em>T</em> (<em>u</em>) + <em>T</em> (<em>v</em>) = (-1, 9, 5)

but

<em>T</em> (<em>u</em> + <em>v</em>) = <em>T</em> (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)

=> <em>T</em> (<em>u</em> + <em>v</em>) ≠ <em>T</em> (<em>u</em>) + <em>T</em> (<em>v</em>)

which means <em>T</em> does not preserve addition, so it is not linear.

4 0

3 years ago

What is P44 ? 16 24 4 1

sergejj [24]

Answer:

Page 44? you mean

Step-by-step explanation:

6 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

What is the simple interest rate if p = $4000, t = 2 years and I = $320

Komok [63]

Answer:

Step-by-step explanation:

interest was $160 for one year.

160/4000 = 0.04 = 4%

4 0

3 years ago

Part 1 - Application

egoroff_w [7]

The measure of the central angle is 89.95 degree or 1.57 radians if the radius of the circle is 7 cm.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)

We have a length of an arc of a circle of radius 7 is approximately 10.99 cm.

The radius r = 7 cm

The arc length l = 10.99 cm

We know,

l = rθ

θ is the central angle.

θ = l/r = 10.99/7 = 1.57 radians

To convert 1.57 radians into the degree multiply it by 180/π

θ = 89.95 degree

Thus, the measure of the central angle is 89.95 degree or 1.57 radians if the radius of the circle is 7 cm.

Learn more about circle here:

brainly.com/question/11833983

#SPJ1

7 0

2 years ago