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raketka [301]
1 year ago
15

Round off .00042557 to three significant digits

Chemistry
1 answer:
Mariulka [41]1 year ago
7 0

Round off .00042557 to three significant digits is = 0.000426

<h3>What is round of value ?</h3>
  • If 5, 6, 7, 8, or 9 come after the number you are rounding, round it up. For instance, 40 is the result of rounding 38 to the nearest ten.
  • If the numbers 0, 1, 2, 3, or 4 come after the number, round it down. If 33 is rounded to the nearest ten, it becomes 30.
  • To estimate a certain number in a context, rounding is a process. Look at the next digit in the correct position to determine how to round a number; if it is less than 5, round down, and if it is 5 or more, round up.

Given

The digit of 00042557

Three significant digits is 0.000426

To learn more about round of value refer to :

brainly.com/question/25297296

#SPJ10

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find the activity coefficient of h , in a solution containing 0.010 m hcl plus 0.040 kclo4. what is the ph of the solution?
Lisa [10]

The activity coefficient of h is 0.05

The ph of the solution is 2.08

To find the activity coefficient, apply the concept of ionic equilibrium

h( activity coefficient)= 1/2CZ²

C is the concentration of species

Z is the charge on individual species

<em>h= 1/2( 0.01 x1²+ 0.04x (-1)²+0.01 x1²+0.04x (-1)²)</em>

<em>h= 0.05 </em>

For the pH of the solution, apply the formula

<em>pH= -log( H⁺x0.83)</em>

<em>pH = - log(0.01x0.83)</em>

<em>= 2.08</em>

To learn more about the pH of the solution, visit brainly.com/question/26767292

#SPJ4

4 0
1 year ago
Calculate the mass in grams of 8.35 × 1022 molecules of CBr4.
antiseptic1488 [7]

Answer: 45.983 g CBr₄

Explanation:

To convert from moles to grams, you know that we will need molar mass and Avogadro's number.

Avogadro's number: 6.022×10²³ molecules/mol

Molar mass: 331.627 grams/mol

Now that we have what we need, you can use these to solve for grams. 8.35*10^2^2molecules CBr_{4} *\frac{1mol}{6.022*10^2^3molecules} *\frac{331.627 g}{1 mol} =45.983 g

Our final answer is 45.983 g CBr₄.

4 0
4 years ago
A 4.000 g sample of iron was heated from 0.0°C to 21.0°C. If it has a specific heat of 0.440 kJ/kg °C, how many kilojoules of he
Mashutka [201]
M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C , c = 0.44kJ/kg°C,

Q = mc(θ₂ - θ₁)

Q = 0.004*0.440*(21 - 0)

Q  =  0.03696 kJ 

0.03696 kJ<span> of heat is absorbed.</span>
6 0
3 years ago
How many moles of N are in 0.241 g of N2O?
gtnhenbr [62]
0.00547 moles of N.
6 0
3 years ago
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A small, hard-shelled fossil that resembles a modern-day ocean organism was found
Paul [167]

Answer:

The desert was one covered by ocean water.

Explanation:

5 0
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