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valkas [14]
3 years ago
7

A rock has a mass of 15 grams and a volume of 5 cm3. What is the density of the rock?

Chemistry
1 answer:
xz_007 [3.2K]3 years ago
3 0
The answers is 3.0 g/cm^3

Explanation:
You use the formula
Density= mass/volume
When they give you mass and volume.

The mass is 15 grams and the volume would be 5 cm^3.

So the density would be
15/5= 3
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Draw the sulfur‑containing product of the oxidation reaction between two 2‑methyl‑1‑propanethiol molecules. Include all hydrogen
kumpel [21]

Answer:

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Explanation:

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4 0
4 years ago
Can some one help me out? I can't chose between A or B
Luba_88 [7]

Answer : If an increase in temperature accompanies a reaction, energy is released. Explanation :In thermodynamics, the reaction is considered as a system and the medium in which the reaction occurs which is usually an aqueous medium is considered as its surrounding. When the heat flows from the system to its surrounding, it increases the temperature of surrounding medium because the heat released by the system is absorbed by its surrounding. This is known as exothermic reaction. An exothermic reaction is always accompanied by energy release. On the other hand, when the heat flows from the surrounding towards system, it decreases the temperature of the surrounding medium. This is known as endothermic reaction. From the above discussion we can say that If an increase in temperature accompanies a reaction, energy is released.

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8 0
3 years ago
Read 2 more answers
When 412.5g of calcium carbonate react with 521.9g of aluminum fluoride,how many grams of each product can be produced
aliya0001 [1]
<h3><u>Answer;</u></h3>

321.8 g CaF2

321.5 g Al2(CO3)3

<h3><u>Explanation;</u></h3>

The equation for the reaction is;  

3 CaCO3 + 2 AlF3 → 3 CaF2 + Al2(CO3)3  

Number of moles of CaCO3 will be;

=(412.5 g CaCO3) / (100.0875 g CaCO3/mol)

= 4.12139 mol CaCO3  

Number of moles of AlF3 will be;

= (521.9 g AlF3) / ( 83.9767 g AlF3/mol)

= 6.21482 mol AlF3

But;

4.12139 moles of CaCO3 would react completely with 4.12139 x (2/3) = 2.74759 moles of AlF3.

Thus; there is more AlF3 present than that, so AlF3 is in excess, and CaCO3 is the limiting reactant.  

Therefore;

Mass of CaF2 will be;

(4.12139 mol CaCO3) x (3/3) x (78.0752 g CaF2/mol) = 321.8 g CaF2  

Mass of Al2(CO3)3 on the other hand will be;

(4.12139 mol CaCO3) x (1/3) x (233.9903 g Al2(CO3)3/mol) = 321.5 g Al2(CO3)3

3 0
4 years ago
All of the following affect toxicity of a substance except*
Studentka2010 [4]

Answer:

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8 0
3 years ago
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