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Andru [333]
3 years ago
13

Lead(II) sulfide, PbS, reacts with oxygen gas to produce lead(II)oxide and dioxide. If 0.500 moles of O2 were consumed using thi

s chemical reaction, how much of lead(II)would be produced?
Chemistry
1 answer:
Andreas93 [3]3 years ago
5 0
I think you mean:
".. reacts with oxygen gas to produce lead (II) oxide and 'sulfur' dioxide..."

The balanced chemical reaction would be
2PbS + 3O2 --> 2PbO + 2SO2

The stiochiometric ratio is this: 3 moles of O2 produces 2 moles of lead (II) oxide. So,

0.500 moles (2/3) = 0.333 moles

Therefore, 0.333 moles of PbO is produced when 0.500 moles of O2 reacts with PbS.
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Ionization energy increase as we move from left to right in the period. This can be explained as when we move from left to right along period new electron is added to the same shell which increase the nuclear charge. Hence results int he decrease in size. Due to this decrease in size more energy is required to remove electron from outermost shell.

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