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3 years ago

5

C. A paramecium is a single-celled organism that lives in ponds. It travels at a rate of 2,000 micrometers per second. What is t

he speed of the paramecium in meters per hour?

1 answer:

ruslelena [56]3 years ago

4 0

Answer:

7.2 meters per hour

Explanation:

It is given that,

The speed of a paramecium is 2,000 micrometers per second.

We need to find the speed of the paramecium in meters per hour.

We know that,

$1\ \mu m=10^{-6}\ m$

and

1 hour = 3600 seconds

$v=2000\ \dfrac{\mu m}{s}\\\\=2000\times \dfrac{10^{-6}\ m}{(\dfrac{1}{3600})\ s}\\\\=7.2\ \text{meters/hour}$

Hence, the speed of the paramecium is 7.2 meters per hour.

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Be sure to answer all parts. The standard enthalpy of formation and the standard entropy of gaseous benzene are 82.93 kJ/mol and

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Answer : The values of $\Delta H^o,\Delta S^o\text{ and }\Delta G^o$ are $33.89kJ,95.94J/K\text{ and }5.299kJ/mol$ respectively.

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Now put all the given values in this expression, we get:

$\Delta H^o=[1mole\times (82.93kJ/mol)]-[1mole\times (49.04J/mol)]$

$\Delta H^o=33.89kJ/mol=33890J/mol$

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$\Delta S^o=S_f_{product}-S_f_{reactant}$

$\Delta S^o=[n_{C_6H_6(g)}\times \Delta S^0_{(C_6H_6(g))}]-[n_{C_6H_6(l)}\times \Delta S^0_{(C_6H_6(l))}]$

where,

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Therefore, the values of $\Delta H^o,\Delta S^o\text{ and }\Delta G^o$ are $33.89kJ,95.94J/K\text{ and }5.299kJ/mol$ respectively.

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