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const2013 [10]
1 year ago
14

Trying figure out to solve the problem. I went wrong somewhere. I have x=35, y=7.7, z=84

Mathematics
1 answer:
yKpoI14uk [10]1 year ago
3 0

Answer:

The value of x,y and z is;

\begin{gathered} x=5.92 \\ y=7.75 \\ z=9.17 \end{gathered}

Explanation:

We want to find the values of x,y and z.

Given the figure in the attached image;

The triangle is divided into two similar triangles and the ratio of their sides will be equal;

\frac{x}{5}=\frac{7}{x}

solving for x; cross multiply

\begin{gathered} x^2=7(5) \\ x^2=35 \\ x=\sqrt[]{35} \\ x=5.92 \end{gathered}

To get the value of y and z, we can use Pythagorean theorem or still applt the method above;

\begin{gathered} \frac{y}{5}=\frac{(5+7)}{y} \\ y^2=5(12) \\ y^2=60 \\ y=\sqrt[]{60} \\ y=7.75 \end{gathered}

For z;

\begin{gathered} \frac{z}{7}=\frac{(5+7)}{z} \\ z^2=7(5+7) \\ z^2=7(12) \\ z^2=84 \\ z=\sqrt[]{84} \\ z=9.17 \end{gathered}

The value of x,y and z is;

\begin{gathered} x=5.92 \\ y=7.75 \\ z=9.17 \end{gathered}

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tensa zangetsu [6.8K]

Answer:

m<3 = 90

C

Step-by-step explanation:

This is a kite. The diagonals intersect each other in such a way that m<1 and m<3 are at right angles. m<3 = 90o

3 0
3 years ago
WILL GIVE BRAINLIEST!
Brrunno [24]

Answer:

The graph is not a function of x because x=0 intersects the graph at two points.

Step-by-step explanation:

The vertical line test is when you draw, well, a vertical line through the graph. the slope of a vertical line is undefined, and the formula written as x=_. So we can eliminate the choices with y=_.

We can clearly see that this graph isn't a function, so we can eliminate the answer choices that say that the graph is a function.

Just in case, draw a line at x=0, to check that it does indeed cross the graph in 2 places.

5 0
3 years ago
If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,
julsineya [31]
<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

<h2>Why?</h2>

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)

(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0
4 years ago
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denis-greek [22]

Answer:

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Step-by-step explanation:

The point slope form of an equation is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

Substituting in what we know

y--4 = 9/4(x-3)

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4 0
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zhenek [66]
They are. There are 12 inches in a foot. 5x12 does equal 60 so they are equal.
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