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velikii [3]
1 year ago
10

A fuelling vehicle finished filling a plane with 12.40 tons of fuelat 10:35. If the fuelling rate is 0.20 ton of fuel per min, a

t whattime did the fuelling start? Give your answer in a 12-hour clockformat, such as 9:00.Enter the answer
Mathematics
1 answer:
BartSMP [9]1 year ago
4 0

Let's define,

X := Total minutes it takes to fill the plane (with fuel)

Then,

X\cdot0.20=12.40

Solving it for X, we get

X=\frac{12.40}{0.20}=62\text{ min}

This means that the vehicle takes 1 h 2 min to fill the plane. If the fuelling finished at 10:35, it began at

10-1\colon35-2=9\colon33

9:33.

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x= 1, 2, 3, 4, 5. y=11\4, 25\4, 39\4, 53\4, 67\4. what equation relates y to x in the values x and y?
larisa86 [58]
(1,11/4)(2,25/4)
slope = (25/4 - 11/4) / (2 - 1) = (14/4) / 1 = 14/4 = 7/2

y = mx + b
slope(m) = 7/2
(1,11/4)...x = 1 and y = 11/4
now we sub and find b, the y int
11/4 = 7/2(1) + b
11/4 = 7/2 + b
11/4 - 7/2 = b
11/4 - 14/4 = b
-3/4 = b

so ur equation is : y = 7/2x - 3/4
4 0
3 years ago
What is 3/2m-m=4+1/2m
Annette [7]

Answer:

answer is 08

Step-by-step explanation:

3/2m-m=4+1/2*m

3m/2-m=4+1/2*m

3m/2-m=4+1/2m

3m/2-m=4+1m/2

3m/2-m=4+1m/2

3m/2-m=4+m/2

3m/2-m=4+m/2

2(3m/2-m)=2(4+m/2)

m=m+8

5 0
3 years ago
When the function ƒ(x) = 4x−2 is evaluated for x = 3, the output is:<br> -4<br> -6<br> -16<br> -none
Mkey [24]

Answer:

None

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 4x - 2

x = 3

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function]:                                                                                f(3) = 4(3) - 2
  2. Multiply:                                                                                                             f(3) = 12 - 2
  3. Subtract:                                                                                                            f(3) = 10
7 0
3 years ago
2HR 37MIN - 1HR 15 MIN
dlinn [17]

Answer:

No

Step-by-step explanation:

2hours and 37min is not the equivilent to 1hour and 15min

6 0
2 years ago
A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
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