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Alexeev081 [22]
1 year ago
10

Reflect quadrilateral CJKM across the y-axis. Find the location of K'.

Mathematics
1 answer:
Montano1993 [528]1 year ago
4 0

K(1,4)\rightarrow K^{\prime}(-1,4)

Explanation

Step 1

find the coordinate of every point of the quadrilateral

C(-3,1)

J(0,1)

K(1,4)

M(4,-2)

Step 2

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

so

(x,y)\rightarrow reflect\text{ across y -Ax is}\rightarrow(-x,y)

therefore

\begin{gathered} C\mleft(-3,1\mright)\rightarrow C^{\prime}(3,1) \\ J\mleft(0,1\mright)\rightarrow J^{\prime}(0,1) \\ K\mleft(1,4\mright)\rightarrow K^{\prime}(-1,4) \\ M(4,-2)\rightarrow M^{\prime}(-4,-2) \end{gathered}

so, the answer is

K^{\prime}(-1,4)

i hope this helps you

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Explanation:

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Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

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The system of hypothesis on this case are:

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Alternative hypothesis: \mu_1 > \mu_2

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Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

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