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3 years ago

Express the ratio below in its simplest form. 18:9

Mathematics

2 answers:

Ulleksa [173]3 years ago

8 0

2:1 is the ratio to that question

natta225 [31]3 years ago

3 0

Answer:

Step-by-step explanation:

$18 :9\\\frac{18}{9} \\Use -3- to- divide- through\\= \frac{2}{1} \\= 2:1$

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A(n) _____ in the money supply will cause interest rates to decrease, which, in turn, causes spending to _____.

sweet-ann [11.9K]

I think the correct answer from the choices listed above is option B. <span>An increase in the money supply will cause interest rates to decrease, which, in turn, causes spending to increase. Decrease of interest rate means money is cheap which will result to more spending.</span>

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2 years ago

Read 2 more answers

Tom has a comic book with 85 pages. He has read 30 of the pages so far. What percentage of the book has Tom read?

Juli2301 [7.4K]

Answer:

35.29%

Step-by-step explanation:

Just divide 30 by 85

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3 years ago

HELP!!

Setler [38]

23. If M' represents the complementary, then is the answer A.

24. The answer is C.

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3 years ago

The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = $\dfrac{2400 \ cm^2}{p}$

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be $\dfrac{2400 \ cm^2}{p} + 20$

The area of the printed material can now be: $A = (p+30)(\dfrac{2400 }{p} + 20)$

= $2400 +20 p +\dfrac{72000}{p}+600$

Let differentiate with respect to p; we have

$\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}$

Also;

$\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}$

For the smallest area $\dfrac{dA}{dp }=0$

$20 - \dfrac{72000}{p^2}=0$

$p^2 = \dfrac{72000}{20}$

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression q = $\dfrac{2400 \ cm^2}{p}$ to solve for q;

q = $\dfrac{2400 \ cm^2}{p}$

q = $\dfrac{2400 \ cm^2}{60}$

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = $\dfrac{2400 \ cm^2}{p} + 20$ = $\dfrac{2400 \ cm^2}{60} + 20$ = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

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3 years ago

Consider a continuous random variable x, which is uniformly distributed between 65 and 85. The probability of x taking on a valu

madam [21]

We will see that the probability of x taking on a value between 75 to 90 is P = 0.5

<h3>How to get the probability?</h3>

We know that x is a continuous random variable uniformly distributed between 65 and 85.

This means that the probability that x value y in the range is such that:

1 = P(y)*(85 - 65) = P(y)*20

1/20 = P(y).

Now, the probability of x taking a value between 75 and 85 is:

P(75 to 85) = (1/20)*(85 - 75) = 10/20 = 0.5

And the probability between 85 and 90 is zero (because the maximum value that x can take is 85, so this part does not affect).

Then we conclude that the probability of x taking a value between 75 to 90 is:

P(75 to 90) = P(75 to 85) + P(85 to 90) = 0.5 + 0 = 0.5

If you want to learn more about probability, you can read:

brainly.com/question/251701

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1 year ago