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Whitepunk [10]
3 years ago
10

Find the measure of each exterior angle of the regular polygon.

Mathematics
2 answers:
svetoff [14.1K]3 years ago
6 0

Answer:

30 degrees

Step-by-step explanation:

(Sum=360)

360/12=30

(We got 12 because there are 12 sides in the polygon!)

Aleks [24]3 years ago
4 0

Answer:

  • 30°

Step-by-step explanation:

  • <em>Sum of exterior angles of the regular polygon is 360°</em>

The pictured is 12-gon

<u>Each exterior angle measures:</u>

  • 360°/12 = 30°
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Find the given derivative by finding the first few derivatives and observing the pattern that occurs. d103 dx103 (sin(x))
aleksandrvk [35]
To find \frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right), we find the first few derivatives and observe the pattern that occurs.

\frac{d}{dx} (\sin{(x)})=\cos{(x)} \\  \\  \frac{d^2}{dx^2} (\sin{(x)})= \frac{d}{dx} (\cos{(x)})=-\sin{(x)} \\  \\ \frac{d^3}{dx^3} (\sin{(x)})= -\frac{d}{dx} (\sin{(x)})=-\cos{(x)} \\  \\ \frac{d^4}{dx^4} (\sin{(x)})= -\frac{d}{dx} (\cos{(x)})=-(-\sin{(x)})=\sin{(x)} \\  \\ \frac{d^5}{dx^5} (\sin{(x)})=  \frac{d}{dx} (\sin{(x)})=\cos{(x)}

As can be seen above, it can be seen that the continuos derivative of sin (x) is a sequence which repeats after every four terms.

Thus,

\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)= \frac{d^{4(25)+3}}{dx^{4(25)+3}} \left(\sin{(x)}\right) \\  \\ = \frac{d^3}{dx^3} \left(\sin{(x)}\right)=-\cos{(x)}

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\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)=-\cos{(x)}.
8 0
3 years ago
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Step by step
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A+B= 180-c




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4 sin c cos 180-2b/2 cos a-(180-a)/ 2

4 sin c cos (90-b ) cos ( A-90)

4 sin c sin b sin A


5 0
4 years ago
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Z=11 is the answer for this problem
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3 years ago
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