Need to use quadratic formula.The solution to the equation 4x² +98 = 0 is
1 answer:
We must solve the quadratic equation
4x² + 98 = 0
using the quadratic formula.
First simplify the equation by dividing both sides by 2:
2x² + 49 = 0
Identify the coeficients:
a = 2
b = 0
c = 49
Calculate delta:
Δ = b² - 4ac
Δ = 0 - 4.2.49
Δ = 0 - 392
Δ = -392
Now let's apply the quadratic formula:
x = (-b ± √Δ) / 2a
x = (-0 ± √-392) / 4
x = ± 14√2i / 4
x = ± 7√2i / 2
So
x' = -7√2i / 2
x'' = 7√2i / 2
Answer: the roots are x' = -7√2i / 2 and x'' = 7√2i / 2
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Answer:
x=4.63
Step-by-step explanation:
Area = (1/2) (base) (height)
20 = (1/2) (x+4) (x)
40 = x²+4x
x²+4x-40=0
Put in quadratic equation:
x=
x=
x=4.63324958071 or x=-8.63324958071
Since x can't be negative in this case we take our answer to be 4.63324958071, which rounds to 4.63