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Katena32 [7]
3 years ago
15

PLEASE HELP 100 points and brainliest. y= 3x — 5 y=6x — 8 solve with elimination

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0
<h2><u>Let's solve for X using elimination</u></h2><h2>\boxed{\fcolorbox{y=3x-5}}</h2><h3>Step 1: Flip the equation around:</h3><h3>\boxed{\fcolorbox{3x-5=y}}</h3><h3>Step 2: Add 5 to either side</h3><h3>\boxed{\fcolorbox{3x-5+5=y+5\\}}    </h3><h3>\boxed{\fcolorbox{3x=y+5\\}}</h3><h3>Step 3: Divide both sides by 3.</h3><h3>\boxed{\fcolorbox{\frac{3x}{3}=\frac{y+5}{3}  \\}}</h3><h3>\boxed{\fcolorbox{x=\frac{1}{3}y+\frac{5}{3}  \\}}              </h3><h3 /><h3>Answer is: \boxed{\fcolorbox{x=\frac{1}{3}y+\frac{5}{3}  \\}}.</h3><h3></h3><h3 />

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Select the assumption necessary to start an indirect proof of the statement. If 3a+7 &lt; 28, then a&lt;7.
pashok25 [27]
When applying indirect proofs, we assume the negation of the conclusion is true, and show that this assumption would lead to nonsense, or contradiction.

In our case we assume a is not smaller than 7, that is we assume a≥7.

a≥7 then, multiplying both sides by 3:
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3a+7≥28,

which is a contradiction because 3a+7 is smaller than 28.

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3 years ago
In what form is the following linear equation written? y-3=2/3(x-1)
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The annual tuition at a specific college was $20,500 in 2000, and $45,4120
nika2105 [10]

Answer: the tuition in 2020 is $502300

Step-by-step explanation:

The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $20500

The fee in 2018 is the 19th term of the sequence. Therefore,

T19 = $45,4120

n = 19

Therefore,

454120 = 20500 + (19 - 1) d

454120 - 20500 = 19d

18d = 433620

d = 24090

Therefore, an

equation that can be used to find the tuition y for x years after 2000 is

y = 20500 + 24090(x - 1)

Therefore, at 2020,

n = 21

y = 20500 + 24090(21 - 1)

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y = $502300

6 0
3 years ago
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Dmitriy789 [7]

Answer:

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