Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>
Step-by-step explanation:
The intercept form of a quadratic equation (parabola):

p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
A is your answer 3.4
Use Pythagorean Theroum
10.2 squared = 9.6 squared + x squared
104= 92.6+x squared
x squared = 11.4
x= 3.37
round x to 3.4
Hope that helps!
15818 ?? This is making me get a headache
Answer:
<h2>Per week: $1041.04</h2><h2>Per month: $4610.32</h2><h2>Per year: 55323.84</h2>
Answer:
I believe the answer is B sorry if I'm wrong