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neonofarm [45]
1 year ago
12

A cylindrical can that has a capacity of 20 m3 will be made. The metal used to build the top costs $10 per square meter while th

e bottom costs $20 per square meter. The material used for the side costs $15 per square meter. What are the dimensions that will minimize the cost?.
Business
1 answer:
Alchen [17]1 year ago
8 0

The dimensions of the cylinder can be used to minimise cost of manufacture.

<h3>How to we find minimised cost?</h3>

Let's ignore the metal's thickness and assume that the material cost to manufacture is precisely proportionate to the surface area of a perfect cylinder.

A=2πr(r+h)

Given that V=1000=r2h and h=1000=r2, we can write

A=2πr(r+1000πr2)

A=2πr2+2000r−1

By setting the derivative to zero, we may determine the value of r that minimises A:

A′=4πr−2000r−2

0=4πr−2000r−2

2000r−2=4πr

2000=4πr3

r=500π−−−√3

r=5.419 + cm

h=1000πr2=10.838 + cm

The can with the smallest surface area has a volume of 1000 cm 3 and measures 5.419+ cm in radius and 10.838+ cm in height. The can has a surface area of 553.58 cm 2. Given a constant volume, the cylinder with diameter equal to height has the least surface area.

Can surface area (cm2) versus. radius (cm), where capacity = 1000cm 3.

Learn more about manufacturing here:

brainly.com/question/17111259

#SPJ4

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Answer:

-$15,315.21

Reject the project

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To find the NPV using a financial calacutor:

1. Input the cash flow values by pressing the CF button. After inputting the value, press enter and the arrow facing a downward direction.

2. After inputting all the cash flows, press the NPV button, input the value for I, press enter and the arrow facing a downward direction.

3. Press compute

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I hope my answer helps you

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