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1 year ago

Find the measure of prq if p is 33, r is 17x + 1 and q is 10x + 1

Mathematics

1 answer:

andrew-mc [135]1 year ago

3 0

The expression we get after measuring prq is 5610x²+ 891x+33.

Given that,

p is 33, r is 17x+1 and q is 10x+1

We have to find the measure of prq.

Take the,

p is 33, r is 17x+1 and q is 10x+1

Now,

prq

By multiply we get an expression

Multiplying each term to each other.

(33)(17x+1) (10x+1)

1st multiply 33 to 17x+1

(561x+33) (10x+1)

Now multiply each 561x with 10x+1 and 33 with 10x+1

5610x²+ 561x+ 330x+33

Adding 561x and 330x

5610x²+ 891x+33

Therefore, The expression we get after measuring prq is 5610x²+ 891x+33.

To learn more about expression visit: brainly.com/question/14083225

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According to the given question.

We have an equation

$\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}$

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

$\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}$

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Multiply both the sides by x.

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Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

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