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Andrei [34K]
10 months ago
14

given that a couple with type a blood and type o blood already have a child with type o blood, construct a punnett square for th

e cross between the two parents.
Biology
1 answer:
Virty [35]10 months ago
6 0

Despite the fact that both parents are still blood type A, Dad has the option of passing either the A or the O gene variant.

Mom can also transmit either an A or an O. As a result, you can see that a child has a 1 in 4 probability, or 25% chance, of having blood type O. However, it is theoretically feasible for two O-type parents to have an AB or B blood type child (although this is even more unlikely). In fact, if you take into account the rule-breaking cases, a child can acquire practically any blood type. Having an A parent and a B parent can result in a child with the blood types A, B, AB, or O.

Learn more about Blood

brainly.com/question/256625

#SPJ4

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In pea plants, long stems are dominant to short stems, purple flowers are dominant to white, and round peas are dominant to wrin
meriva

Assuming the genes are not linked nor interacting with each other, the expected number of long stemmed plants with purple flowers, producing wrinkled peas, L-P-rr, is 288.

<h3>Available data</h3>

  • long stems are dominant to short stems
  • purple flowers are dominant to white,
  • round peas are dominant to wrinkled

  • Each trait is determined by a single, different gene.

  • A heter0zyg0us plant is self-crossed
  • F1) 2,048 descendants

Let us name te alleles as follows

  • L ⇒ Long stem
  • l ⇒ Short stem
  • P ⇒ Purple flowers
  • p ⇒ white flowers
  • R ⇒ Round peas
  • r ⇒ wrinkled peas

Cross) heter0zyg0us plant is self-crossed

Parental) LlPpRr

Gametes) LPR, LPr, LpR, Lpr, lPR, lPr, lpR, lpr

Assuming that these genes are not linked nor interacting with each other, to make the calcs easier we will make crosses considering each gene separately.

  • Stems

Parental) Ll  x  Ll

F1) 1/4 LL, 2/4 Ll, 1/4 ll

     <u>3/4 long stem,</u> 1/4 short stem

  • Flower color

Parental) Pp  x  Pp

F1) 1/4 PP, 2/4 Pp, 1/4 pp

     <u>3/4 purple flowers</u>, 1/4 white flowers

  • Peas

Parental) Rr  x  Rr

F1) 1/4 RR, 2/4 Rr, 1/4 rr

     3/4 round peas, <u>1/4 wrinkled peas</u>

Now, we will get the proportion of individuals with long stems, purple flowers, producing wrinkled peas, L-P-rr

<u><em>Note</em></u><em>: The symbol - is representing either a dominant or a recessive allele.</em>

From the crosses, we know that

  • 3/4 are long stemmed,
  • 3/4 have purple flowers, and
  • 1/4 have wrinkled peas.

To get the proportion of individuals expressing all these traits together, we just need to multiply these values.

3/4 L- x 3/4 P- x 1/4 rr =<u> 9/64 L-P-rr</u>

Knowing that  the total number of plants is 2,048 and that there are 64 possible gametes combinations from this cross, we will use the proportion 9/64 to get the number of plants with these traits.

64 ------------- 2,048 plants

9 -------------- X = (9 x 2048) / 64 = 288 plants.

<em>We expect to find 288 long stemmed plants with purple flowers, producing wrinkled peas.</em>

<em />

<em />

You will learn more about trihybrid crosses at

brainly.com/question/21942441

brainly.com/question/7333760

brainly.com/question/6764853

4 0
2 years ago
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