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Hitman42 [59]
1 year ago
5

Solve this system of linear equations. Separatethe x- and y-values with a comma.13x = -21 - 6y- 8x = 36 + 6yEnter the correct an

swer.DONE?
Mathematics
1 answer:
Ivenika [448]1 year ago
7 0

Solution:

Let:

\begin{gathered} 3x=-21-6y\text{   (Equation 1)} \\ -8x=36+6y\text{   (Equation 2)} \end{gathered}

To get the value of x, we add the Equation 1 and 2.

13x = -21 - 6y

+ - 8x = 36 + 6y

We will get:

5x=15

Calculate:

x= 3

Since x= 3, we plug in what we know:

13x = -21 - 6y

13(3) = -21 - 6y

39 = -21 - 6y

Simplify and rearrange:

-6y = 39 + 21

-6y= 60

Calculate:

y= -10

Therefore, the values are x= 3, y= -10 or (3,-10).

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Slav-nsk [51]

Answer:

5 should be correct answer

8 0
3 years ago
If you don’t know the answer don’t answer it pls help me out if you do tho!
antoniya [11.8K]

Answer: x = 8

Step-by-step explanation:

Hello again XD.

This is a coordinate plane and all the angles on a coordinate plane add up to 360°

Divide 360 by 4 to get the measurement of the section we are working in.

360/4 = 90°

This means it is complementary and complementary angles state that both separate angles added together = 90°

therefore,

6x + 2 + 40 = 90

combine like terms:

6x + 42 = 90

now subtract 42 from both sides

6x = 48

divide 6 from both sides to get:

x = 8

Let me know if you have any more questions you want answered and I hope I explained this well.

5 0
2 years ago
It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
Question choices<br> 85<br> 50<br> 42.5<br> 59<br> 1.7<br> PLEASE HELP PLS
aleksley [76]

Answer:

42.5

Step-by-step explanation:

Multiply 50 by 0.85, which equals 42.5.

6 0
3 years ago
A family installs and fills an aboveground pool. The swimming pool costs $850 to install, and it costs $75 per thousand gallons
kari74 [83]

Answer:

925????

Step-by-step explanation:

6 0
3 years ago
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