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2 years ago

The area of a rectangle is 600 square meters the width is 30 meters what is the length

Mathematics

1 answer:

kap26 [50]2 years ago

6 0

Answer:

l = 20 m

Step-by-step explanation:

600/30 = 20

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The midpoint of line MN is P(5,5). One of the end points in M(-4,2). Find the coordinate of endpoint N.

Greeley [361]

-4 + x    2 + y
------- = 5 and   ------ = 5
2       2

so x = 10 + 4 = 14 and y = 10 - 2 = 8

endpoint N = (14,8)

7 0

2 years ago

Let

Citrus2011 [14]

Answer:

hi or high

Step-by-step explanation:

so you right the world h and i and cobine them to make hi or high same thing

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3 years ago

Each leg of 45 degree -45 degree -90 degree triangle measure 12 cm what is the length of the hypotenuse

Yuri [45]

A = b = 12 cm

<span>Pythagorean theorem
</span>
$a^2+b^2=c^2\\\\ c^2=a^2+a^2\\\\ c^2=2a^2\\\\ c=\sqrt{2a^2}$

$c=a\sqrt2$ formula

$c=12\sqrt{2} \ (cm)$ <-- Answer

3 0

3 years ago

Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really up

wlad13 [49]

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

$a(t)=9.8$

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

$\int \:a\left(t\right)dt=\int \:9.8dt$

$v(t)=9.8t+C$

we are given

v(0)=35m/s

we can use it and find C

$v(0)=9.8*0+C$

$35=9.8*0+C$

$C=35$

now, we can plug it back

$v(t)=9.8t+35$

we know that

integral of velocity is height

we can integrate it again

$\int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt$

$s(t)=\int \:\left(9.8t+35\right)dt$

$s(t)=4.9t^2+35t+C$

now, we have

s(0)=6

we can use it and find C

$s(0)=4.9(0)^2+35(0)+C$

$6=4.9(0)^2+35(0)+C$

now, we can plug back C

$C=6$

and we get

$s(t)=4.9t^2+35t+6$ .............Answer

4 0

3 years ago

Read 2 more answers

Item 19 A cylindrical container of four rubber balls has a height of 20 centimeters and a diameter of 5 centimeters. Each ball i

Lady_Fox [76]

First you need to find the volume of the cylinder. Then find the volume of all 4 rubber balls (spheres). Subtract the cylinder's volume by the spheres' volumes.

Volume of cylinder: πr²h
π2.5²(20) = 392.7 cm³

Volume of sphere: 4/3πr³
4/3π2.5³ = 65.45 cm³

392.7 - 65.45 = 327.25

The amount of space in the container unoccupied by the rubber balls is 327 cm³.

7 0

3 years ago