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hoa [83]
2 years ago
11

PLZ HELP ASAP

Mathematics
2 answers:
Sav [38]2 years ago
5 0

Answer:

The height = 18 inches

Step-by-step explanation:

The volume = area of the base × height

Area of the base = 40.5 inches²

The volume = 729 inches³

729 = 40.5 × height

Height = 729 ÷ 40.5 = 18 inches

Yuri [45]2 years ago
3 0
I believe it might be 18 have a great day!
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Someone please help asap
joja [24]
Solve the equation of the function for n.

a(n) = 3n - 20

a = 3n - 20

a + 20 = 3n

(a + 20)/3 = n

n = (a + 20)/3

n(a) = (a + 20)/3
6 0
3 years ago
Rewrite the expression g+1/6d-3/4g+1/9g-g+1/4d in standard from by combining like terms I need this ASAP AND I NEED ALL STEPS TO
GarryVolchara [31]

Answer:

(5/12)d - (23/36)g

Step-by-step explanation:

First you can eliminate g and -g to get (1/6)d - (3/4)g + (1/9)g + (1/4)d. Then you need to get common denominators to add like terms together.

1/6 = 4/24 and 1/4 = 6/24. Add them together to get (10/24)d or (5/12)d.

-3/4 = -27/36 and 1/9 = 4/36. Add them together to get (-23/36)g.

So in standard form, (5/12)d - (23/36)g

5 0
3 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
3 years ago
There is a total of 80 firefighters in a town. There are 4 fire departments in the town: North, South, East, and West. The North
andreev551 [17]
Shshshshshwlkwkskzjsis
7 0
3 years ago
Find the gradients for line A and B.<br><br> See pic attached
pogonyaev
Gradient is the difference between the y-axis and the x-axis
Gradient = y2-y1/x2-x1
Choose any two point making a triangle
Line B (0,8) (4,0)
This makes a triangle please go look at the graph once again! The the triangle should not have half squares but full!
Line A (5,14)(2,2)
Now plug in the variable
The difference between the Y and X
Line B 0-8/4-0
Line B gradient =-2
Line A 2-14/2-5
Line A gradient = +4

Finalized answer
Line B gradient = -2
Line A gradient = +4
8 0
2 years ago
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