Answer:
06959399449444rifotvovty5
To solve this problem,you need to use the formula d = rd (distance = rates x time)She runs at a speed of 7 mph and walks at a speed of 3 mph. Her distance running is d = 7trwhere tr is the time she spends running Her distance walking isd = 3twwhere tw is the time she spends walking The distances are the same so7tr = 3tw We also know that the total time is 4 hourstr + tw = 4tr = 4-tw Substitute this value of tr in the first equation7tr = 3tw7(4-tw) = 3tw28-7tw = 3tw28 = 10tw2.8 = tw Denise will spend 2.8 hours (2 hours, 48 minutes) walking back and 1.2 hours (1 hour, 12 minutes running.
Hope I helped :)
Answer:
number 10
dy/dx =(dy/dt).(dt/dx)
now find
dy/dt=4t-1. , dt/dx=1
so : dy/dx=(4t-1).(1)
dy/dx= 4t-1 ,we have x=t-3-----> t=x+3
subtitute at t
dy/dx= 4(x+3)-1=4x+12-1= 4x+11
I suppose the / are absolute value lines.... so ill answer it that way, -(-2) simplifies to 2. -/-2/ simplifies to -2
Answer:
2y=5x+2c
Step-by-step explanation: