Answer:
cos ∠CBD = - 4√41 / 41
Step-by-step explanation:
AB = 4 ΔABC = (4 x AC) / 2 = 10
AC = 5
BC = √5² + 4² = √41
cos ∠CBD = cos (180° - ∠CBA) = cos 180° cos ∠CBA + sin 180° sin ∠CBA
(cos 180° = - 1 sin 180° = 0 cos ∠CBA = 4 / √41 )
cos ∠CBD = (-1) x cos ∠CBA = - 4 / √41 = - 4√41 / 41
Answer:
11200 for 7 engines for a total of 80 hours
Step-by-step explanation:
You have 8 engines burning 12000 .for 10 hours.
Divide 10 hours into 12000=1200 PER hour.
1200 ÷8 engines = 140 per hour per engine.
140 × # of hours (12)=1680 for 12 hours per engine.
# of engines × 1680 for 12 hour/per engine
5×1680 = 8400 of fuel for 12 hours/5 engine
Then you have 2 that runs 10 hours
2 × 140 per hour per engine =280 × 10 =2800 for 2 engines for 10 hours
8400. + 2800= 11200 of fuel for 6 engines
Hello from MrBillDoesMath!
Answer:
"-3" is added to a sequence member to get the next number. This next two terms are -14 and -17
Discussion:
Note that -2 -3 = -5 and
-5 -3 = -8 and
-8 - 3 = -11
"-3" is added to a sequence member to get the next number. This implies that the next two terms are -11 -3 = -14 and -14 -3 = -17
Regards,
MrB
Answer:
15/4, or 3.75
Step-by-step explanation:
all i really did was plug it into the calculator like so: (3/4)/(1/5) and thats what came out
7/8 owns bike
1/8 dont
difference is 6/8
6/8= 72
96 students were surveyed, if you solve that equation^