Question

Logarithm 2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen ion concentration (H^+,measured in moles/liter) of the fluid using the model shown below:pH = -log(H^+)A lab technician finds that a sample of fluid has a pH of 4.5. What is the hydrogen ion concentration of the fluid?

Answer 1

ok. We are given the following equation:

$ph=-\log (H)$

Where:

$\begin{gathered} P=\text{ alkalinity} \\ H=\text{ hydrogen ion concentration} \end{gathered}$

Since we are asked to determine "H" we will solve for "H" in the equation. To do that we will first multiply both sides by -1:

$-ph=\log (H)$

Now, we will use the following property of logarithms:

$\log _aB=c\rightarrow B=a^c$

Applying the property and having into account that:

$\log (H)=\log _{10}(H)$

We get:

$10^{-pH}=H$

Now we substitute the given value of "pH = 4.5":

$10^{-4.5}=H$

Solving the operation:

$0.000032=H$

Therefore, the hydrogen ion concentration of the fluid is 0.000032