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Montano1993 [528]
3 years ago
14

What is the reciprocal of 3? (As a fraction)

Mathematics
2 answers:
Bond [772]3 years ago
7 0
The reciprocal is always the opposite so in this case it would be 1/3. Because since it was 3/1 the opposite would be 1/3
grigory [225]3 years ago
3 0

Answer:

1/3

Step-by-step explanation:

The reciprocal of a number is 1 divided by the number.

The reciprocal of 3 is 1 divided by 3, or simply 1/3.

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A sector with a central angle measure of 4pi/5
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Answer: the area is 20 square centimeters.

Step-by-step explanation:

The area of an arc of angle x in a circle of radius r is:

A = (x/3.14)*3.14*r^2 = x*r^2

here we have x = (4/5)*3.14 and r = 5cm

Then the area is:

A = (4/5)*(5cm)^2 = 20cm^2

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3 years ago
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if the first 15 sandwiches sold at a restaurant one day, 9 were club sandwiches. at the same rate, how many sandwiches would hav
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Answer:

54 I think

Step-by-step explanation:

I just did 15 divided by 9 and got 5/3 and then did 90 divided by 5/3 and got 54

6 0
3 years ago
I do not understand this problem
Natali [406]
I think its saying find the mixed numbers but keep the denominator

4 0
3 years ago
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A concentric-tube heat exchanger cools hot water owing at 1 kg/s from 80C to 30C. It uses air owing at 5 kg/s to perform this co
nordsb [41]

Answer:

The log-mean-temperature-difference is 24.03⁰C

Step-by-step explanation:

First we need to know if the heat exchanger is in parallel flow or counter-flow. However, counter flow arrangement is best used to recover heat.

L.M.T.D for counter flow is given as;

L.M.T.D =\frac{(T_h_f_1 -T_c_f_2)-(T_h_f_2 -T_c_f_1)}{2.3log[\frac{T_h_f_1 -T_c_f_2}{T_h_f_2 -T_c_f_1}]}

where;

Thf₁ is the initial temperature of the hot fluid = 80°C

Tcf₂ is the final temperature of the cold fluid = 51.5°C

Thf₁ - Tcf₂ = 80 - 51.5 = 28.5⁰C

Thf₂ is the final temperature of the hot fluid = 30°C

Tcf₁ is the initial temperature of the cold fluid = 10°C

Thf₂ - Tcf₁ = 30 - 10 = 20⁰C

L.M.T.D = \frac{28.5 -20}{2.3Log[\frac{28.5}{20}]} \\\\L.M.T.D = \frac{8.5}{0.3538} =24.03^oC

Therefore, the log-mean-temperature-difference is 24.03⁰C

3 0
3 years ago
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HELP ASAP PLEASE!
AfilCa [17]

Answer:

Hope this is right.

1. 7(4x-5)

2. 28x-35

Step-by-step explanation:

7 0
3 years ago
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