<span /><span>TLDR: Equation is 5(10 + x) = 6x. x = 50, so Sheila deposited $50 each 6 trips. Sherri deposited $60 each 5 trips. Both of them deposited $300 in total.
</span>Sherri deposited $10 more into her bank account than Sheila each 5 times. Expression: 5(x + 10).
Sheila deposited money 6 times
Expression: (6)(x) or 6x
Put it all together and the equation is 5(x+10)=6x.
Solve by distributing the 5 on the right side of the equation 5(x+10) to get 5x + 50 = 6x. Subtract 5x on both sides of equation. 5x - 5x + 50 = 6x - 5x to get 50 = 1x. Divide by 1 on each side to isolate the variable. x = 50. Sheila paid $50 in each of her 6 deposits, so she deposited $300 in total. Check the equation by replacing x with 50.
Sherri paid $60 in each of her 5 deposits because 50 + 10 is 60. 60 by 5 is also $300.
Answer:
2/7x +3=9
x=21
Step-by-step explanation:
Let the unknown be x.
Take 3 to the other side so: 2/7 multiplied by x= 6
Divide 6 by 2/7 to get the answer;
Therefore x=21
Sub back into equation to check answer.
Answer:
b) The width of the confidence interval becomes narrower when the sample mean increases.
Step-by-step explanation:
The confidence interval can be calculated as:

a) The width of the confidence interval becomes wider as the confidence level increases.
The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.
b) The width of the confidence interval becomes narrower when the sample mean increases.
The above statement is false. As the sample mean increases the width of the confidence interval increases.
c) The width of the confidence interval becomes narrower when the sample size n increases.
The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.
There are a total 40 cars
and there is x yellow cars
and there are nine times as much white cars (9x white cars) lol
so x+9x=40
simplify 10x=40
divide both sides by ten 10x/10=40/10
x=4
we are looking for the number of WHITE cars sooo we multiply by 9-
9x=36
how is this "hardddd" no offence*
sorry im a mean person
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x