1st number = n
2nd number = n+1
3rd number = n+2
sum of the squares of 3 consecutive numbers is 116
n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.
The system of equations representing these costs are; y = 7.5x and y = 5.5x + 10
<h3>How to find the equation of a line?</h3>
The slope of the first line is;
m = (y2 - y1)/(x2 - x1)
m = (32 - 10)/(4 - 0)
m = 5.5
Now, the first coordinate has a y-intercept of 10. Thus, the equation here for the cost is; y = mx + c = 5.5x + 10
The slope of the second line is;
m = (y2 - y1)/(x2 - x1)
m = (15 - 0)/(2 - 0)
m = 7.5
Now, the first coordinate has a y-intercept of 0. Thus, the equation here for the cost is; y = mx + c = 7.5x + 0 = 7.5x
Thus, the system of equations representing these costs are;
y = 7.5x and y = 5.5x + 10
Read more about Equation of a line at; brainly.com/question/13763238
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x + 2x + 9y - 7y
3x + ( 9y - 7y )
3x + 2y
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Answer:
Step-by-step explanation:
The reference angle is an acute angle that angle in standard position makes with the positive x-axis.
The given angle in radians is
This angle is already acute and hence it is itself a reference angle.
The reference angle of any angle in the first quadrant is the same angle.
