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3 years ago

Help meee please !!!!!

Mathematics

1 answer:

Helen [10]3 years ago

4 0

Answer:

The same as GH to JK

Step-by-step explanation:

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Can someone please help me? If it is correct ai will give Brainliest Thank you

Rasek [7]

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Answer:

Step-by-step explanation:

Collecting terms of the expression, we have ...

x + 0.1x = x(1 +0.1) = 1.1x

In words, adding 10% is the same as multiplying the value by 1.1. Choice A is appropriate.

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2 years ago

Provide an example of a function that does not have an inverse function. How do you prove that it is not a function?

SOVA2 [1]

Answer:

f(x) = x^2 is a classic example

f( 3 ) = 9 and

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2 years ago

Which graph would you want to use if you worked for Brand A and wanted to show that your product is preferred almost as often as

jasenka [17]

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3 years ago

Read 2 more answers

Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

zmey [24]

Answer:

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

$hypotenuse^2=(5)^2+(12)^2$

$hypotenuse^2=25+144$

$hypotenuse^2=169$

Taking square root on both sides.

$hypotenuse=13$

In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

$\sin \theta = \dfrac{5}{13}$

$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

In second quadrant only sine and cosecant are positive.

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

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3 years ago

PLEASE HELP!! Will give brainliest! A) Greater than B) Less than C) Equal to

Likurg_2 [28]

Its equal to the graph

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3 years ago