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posledela
11 months ago
11

Select ALL statements that are true about the functionDomain: [1, 11]Domain: [0, 13]Domain: (0, 13)Range: (1, 11)Range: [1, 11]R

ange: [0, 13]Maximum: (10, 11)Maximum: (3, 1)Minimum: (3, 1)Minimum: (10, 11)

Mathematics
1 answer:
zzz [600]11 months ago
8 0

Domain : [1 , 11] -------- True

Domain : [0, 13] ---------- False

Domain : ( 0, 13) ----------True

Range : (1, 11) ----------------False

Range : [1, 11] ----------------False

Range : [0 , 13]---------------True

Maximum: (10, 11) ----------- True

Maximum : (3, 1 ) -------------False

Minimum : (3 , 1 ) -------------True

Minimum : (10 , 11 ) -----------False

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Step-by-step explanation:

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3 years ago
A small company can produce up to 200 handmade sandals a month. The monthly cost, C, of producing x sandals is C(x) = 1000 + 5x.
wariber [46]
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3 0
3 years ago
I'm having trouble with algebraic fractions . 3/2n-8/3=-29/12
nadezda [96]

what we can do is hmmmm get the LCD of all fractions, and multiply both sides by that LCD, let's see, we have denominators of 2, 3 and 12, so we can use the LCD of 12, and multiply both sides by 12 to do away with the denominators.

\bf \cfrac{3}{2}n-\cfrac{8}{3}=-\cfrac{29}{12}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{3}{2}n-\cfrac{8}{3} \right)=12\left( -\cfrac{29}{12} \right)}\implies (6)3n-(4)8=(1)-29 \\\\\\ 18n-32=-29\implies 18n=3\implies n=\cfrac{3}{18}\implies n=\cfrac{1}{6}

5 0
3 years ago
AT the local zoo, the aquarium can be seen from the Reptile Room and the Amphibian Arena. What is the total area of both rooms a
BartSMP [9]

Answer:

The total area of both rooms and the aquarium is equal to 10,932 ft²

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

the length sides of Aquarium are

(83-32) x (72-52)-----> 51 ft x 20 ft

Area reptile room=(83*72)-area of aquarium----> 83*72-51*20---> 4,956 ft²

[ total area of both rooms]=2*4,956-----> 9,912 ft²

I'm assuming that the two areas are equal

Area of aquarium=51*20=1,020 ft²

therefore

the total area of both rooms and the aquarium is equal to

9,912 ft²+1,020 ft²=10,932 ft²

6 0
3 years ago
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