Answer:
27 buckets.
Step-by-step explanation:
If we multiply the 9 gallons of paint by the denominator of the number of gallons that fit into one of the buckets we can discover the answer to the question.
Brainliest please.
<span>I will assume the more likely selection of $10 per sandal as opposed to $0.05 per sandal.
So with the formulas
c = 1000 + 5x
r = 75x - 0.4x^2
Sandals Cost Revenue Profit or Loss
0 $1,000.00 $0.00 -$1,000.00
1 $1,005.00 $74.60 -$930.40
2 $1,010.00 $148.40 -$861.60
3 $1,015.00 $221.40 -$793.60
4 $1,020.00 $293.60 -$726.40
5 $1,025.00 $365.00 -$660.00
6 $1,030.00 $435.60 -$594.40
7 $1,035.00 $505.40 -$529.60
8 $1,040.00 $574.40 -$465.60
9 $1,045.00 $642.60 -$402.40
10 $1,050.00 $710.00 -$340.00
11 $1,055.00 $776.60 -$278.40
12 $1,060.00 $842.40 -$217.60
13 $1,065.00 $907.40 -$157.60
14 $1,070.00 $971.60 -$98.40
15 $1,075.00 $1,035.00 -$40.00
16 $1,080.00 $1,097.60 $17.60
17 $1,085.00 $1,159.40 $74.40
18 $1,090.00 $1,220.40 $130.40
19 $1,095.00 $1,280.60 $185.60
20 $1,100.00 $1,340.00 $240.00
As you can see 16 sandals and up is profitable.
At what production levels will the company lose money?
a. between 0 and 10 or between 150 and 190 pairs, inclusive
150 and 190
c. between 10 and 20 or between 50 and 100, inclusive
If you add up the profit between 10 and 20 you will get $-484 so 50 and 100
b. between 0 and 15 or between 160 and 200 pairs, inclusive
160 and 200
d. between 15 and 35 or between 75 and 125, inclusive
Neither 15 and 35 or 75 and 125 will lose money.</span>
what we can do is hmmmm get the LCD of all fractions, and multiply both sides by that LCD, let's see, we have denominators of 2, 3 and 12, so we can use the LCD of 12, and multiply both sides by 12 to do away with the denominators.

Answer:
The total area of both rooms and the aquarium is equal to 10,932 ft²
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
the length sides of Aquarium are
(83-32) x (72-52)-----> 51 ft x 20 ft
Area reptile room=(83*72)-area of aquarium----> 83*72-51*20---> 4,956 ft²
[ total area of both rooms]=2*4,956-----> 9,912 ft²
I'm assuming that the two areas are equal
Area of aquarium=51*20=1,020 ft²
therefore
the total area of both rooms and the aquarium is equal to
9,912 ft²+1,020 ft²=10,932 ft²