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balu736 [363]
2 years ago
11

Find the sum and choose the correct answer. 5n 3 + 4n 2 - 9 and -2n 3 + 7n - 5

Mathematics
2 answers:
mezya [45]2 years ago
8 0
<h2><em>Answer:</em></h2><h2><em>3</em><em>n</em><em>^</em><em>3</em><em>+</em><em>4</em><em>n</em><em>^</em><em>2</em><em>+</em><em>7</em><em>n</em><em>-</em><em>1</em><em>4</em></h2>

<em>Solution</em><em>,</em>

<em>5</em><em>n</em><em>^</em><em>3</em><em>+</em><em>4</em><em>n</em><em>^</em><em>2</em><em>-</em><em>9</em><em>+</em><em>(</em><em>-2n^</em><em>3</em><em>+</em><em>7</em><em>n</em><em>-</em><em>5</em><em>)</em>

<em>=</em><em> </em><em>5</em><em>n</em><em>^</em><em>3</em><em>+</em><em>4</em><em>n</em><em>^</em><em>2</em><em>-</em><em>9</em><em>-</em><em>2</em><em>n</em><em>^</em><em>3</em><em>+</em><em>7</em><em>n</em><em>-</em><em>5</em><em>.</em>

<em>Combine </em><em>the </em><em>like </em><em>terms,</em>

<em>=</em><em>5</em><em>n</em><em>^</em><em>3</em><em>-</em><em>2</em><em>n</em><em>^</em><em>3</em><em>+</em><em>4</em><em>n</em><em>^</em><em>2</em><em>+</em><em>7</em><em>n</em><em>-</em><em>9</em><em>-</em><em>5</em>

<em>=</em><em>3</em><em>n</em><em>^</em><em>3</em><em>+</em><em>4</em><em>n</em><em>^</em><em>2</em><em>+</em><em>7</em><em>n</em><em>-</em><em>1</em><em>4</em>

<em>hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

valkas [14]2 years ago
7 0

Answer:

=  3 {n}^{3}  + 4 {n}^{2}  + 7n - 14 \\

Step-by-step explanation:

5 {n}^{3}  + 4{n}^{2}  - 9 + ( - 2 {n}^{3}  + 7n - 5) \\ 5 {n}^{3}  + 4 {n}^{2}  - 9 - 2 {n}^{3} + 7n  - 5 \\ =  3 {n}^{3}  + 4 {n}^{2}  + 7n - 14

hope this helps

brainliest appreciated

good luck! have a nice day!

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Part A

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MAXImum [283]
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6 0
3 years ago
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KATRIN_1 [288]

Answer: x^{\frac{2}{3} }

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

(x^{a})(x^{b}) = x^{a + b} <em>(Exponents with the same base that are being multiplied together can have the exponents added)</em>

(x^{a})^{b} = x^{(a)(b)} <em>(A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)</em>

<em />

Let's apply it!

First, let's simplify what's inside the parenthesis.

x^{\frac{4}{3} } x^{\frac{2}{3} } <em>(Remember, they have the same base of "x", so we can add the exponents)</em>

x^{\frac{4}{3} + \frac{2}{3} } = x^{\frac{6}{3} } = x^{2}

Now we have (x^{2})^{\frac{1}{3} }. Let's use the second rule.

(x^{2})^{\frac{1}{3} } = x^{\frac{2}{3} }

Hope this helps! :^)

7 0
3 years ago
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