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Ray Of Light [21]
1 year ago
6

(a) Select all that describe BD. B Perpendicular bisector of AC Angle bisector of LB Median of AABC Altitude of A ABC A None of

the above (b) Select all that describe HI. Perpendicular bisector of FG Angle bisector of ZH I Median of AFGH Altitude of AFGH None of the above (c) Select all that describe JM.
Mathematics
1 answer:
Fynjy0 [20]1 year ago
3 0

a) Altitude of triangle ABC

b) Angle bisector of angle H

c) Median of triangle JKL

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On the coordinate grid of a map. Jeff's house is located at (9,5). Hannah's house is at (-5,-5). Kenya's house is located at the
Andru [333]
The midpoint formula is \frac{ x_{1} +  x_{2} }{2},  \frac{ y_{1}+ y_{2}  }{2}
So just plug in the corresponding coordinates in the correct place to get the midpoint.
x_1=-5 ; x_2=9 ;  y_1=-5 ; y_2=5
((-5 + 9)/2 , (-5 + 5)/2)
(4/2 , 0/2)
(2,0) is where Kenya's house is(which is the midpoint). 

The distance formula is a bit more complicated than that. The distance formula is D=\sqrt{({y_{2}- y_{1} }^{2})  + ({ x_{2}- x_{1}}^{2} )  }
In this case now, your looking for the distance from Hannah's house to Kenya's house.
D=\sqrt{(-5-2)^{2} + (-5-0)^{2}  }
=\sqrt{49+25}
=\sqrt{74} ≈8.6023
8 0
3 years ago
Read 2 more answers
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21m. what is the volume of the sphere.​
Goshia [24]

Answer:

The volume of the sphere is 14m³

Step-by-step explanation:

Given

Volume of the cylinder = 21m^3

Required

Volume of the sphere

Given that the volume of the cylinder is 21, the first step is to solve for the radius of the cylinder;

<em>Using the volume formula of a cylinder</em>

The formula goes thus

V = \pi r^2h

Substitute 21 for V; this gives

21 = \pi r^2h

Divide both sides by h

\frac{21}{h} = \frac{\pi r^2h}{h}

\frac{21}{h} = \pi r^2

The next step is to solve for the volume of the sphere using the following formula;

V = \frac{4}{3}\pi r^3

Divide both sides by r

\frac{V}{r} = \frac{4}{3r}\pi r^3

Expand Expression

\frac{V}{r} = \frac{4}{3}\pi r^2

Substitute \frac{21}{h} = \pi r^2

\frac{V}{r} = \frac{4}{3} * \frac{21}{h}

\frac{V}{r} = \frac{84}{3h}

\frac{V}{r} = \frac{28}{h}

Multiply both sided by r

r * \frac{V}{r} = \frac{28}{h} * r

V = \frac{28r}{h} ------ equation 1

From the question, we were given that the height of the cylinder and the sphere have equal value;

This implies that the height of the cylinder equals the diameter of the sphere. In other words

h = D , where D represents diameter of the sphere

Recall that D = 2r

So, h = D = 2r

h = 2r

Substitute 2r for h in equation 1

V = \frac{28r}{2r}

V = \frac{28}{2}

V = 14

Hence, the volume of the sphere is 14m³

4 0
3 years ago
Read 2 more answers
​A manager wants to know if the mean productivity of two workers is the same. For a random selection of 30 hours in the past​ mo
vekshin1

Answer:

A.The data should be treated as paired samples. Each pair consists of an hour in which the productivity of the two workers is compared.

Explanation:

If the mean productivity of two workers is the same.

For a random selection of 30 hours in the past month, the manager compares the number of items produced by each worker in that hour.

There are two samples and the productivity of the two men is paired for each hour.

7 0
3 years ago
Jord Problems
maxonik [38]
They are at the 31 yard line
3 0
3 years ago
Suppose a circle has a radius of 13 inches. How far would a 24 inch chord be from the center of the circle? (Hint: Draw a diagra
lys-0071 [83]

Answer:

Step-by-step explanation:

Directions

  • Draw a circle
  • Dear a chord with a length of 24 inside the circle. You just have to label it as 24
  • Draw a radius that is perpendicular and a bisector through the chord
  • Draw a radius that is from the center of the circle to one end of the chord.
  • Label where the perpendicular radius to the chord intersect. Call it E.
  • You should get something that looks like  the diagram below. The only thing you have to do is put in the point E which is the midpoint of CB.

Givens

AC = 13 inches                   Given

CB = 24 inches                  Given

CE = 12 inches                    Construction and property of a midpoint.

So what we have now is a right triangle (ACE) with the right angle at E.

What we seek is AE

Formula

AC^2 = CE^2 + AE^2

13^2 = 12^2 + AE^2

169 = 144 + AE^2                     Subtract 144 from both sides.

169 - 144 = 144-144 + AE^2     Combine

25 = AE^2                                Take the square root of both sides

√25 = √AE^2

5 = AE

Answer

The 24 inch chord is 5 inches from the center of the circle.

4 0
2 years ago
Read 2 more answers
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