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Vanyuwa [196]
2 years ago
12

What slope would make the lines perpendicular? y. = }x+6 = [?]x+ 3

Mathematics
1 answer:
Montano1993 [528]2 years ago
3 0

Answer:

to make it perpendicular the slope as to be -5 (opposite reciprocal of the original)

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Is 4 3/5 rational or irrational?
Vsevolod [243]

Answer:

It is rational

7 0
2 years ago
Read 2 more answers
Extra points!!no links tho
Naddik [55]

Answer:

<h3>              a. the  vertex represents a minimum point</h3><h3>              b.  f(x) = (x + 5)² - 5</h3>

Step-by-step explanation:

a.

a = 1 > 0  ← that means the parabola opens up, so the vertex is minimum of the function

b.

  f(x)=x^2+10x+20\\\\f(x)=\underline{x^2+10x+25} - 25+20\\\\f(x)=(x+5)^2-5

5 0
3 years ago
A triangle forms the front of the Pantheon in Rome, Italy. Classify the triangle based on its sides. Then classify it based on i
SVETLANKA909090 [29]

Answer:

(See explanation for further details)

Step-by-step explanation:

Classification based on sides:

Equilateral - Three sides with same length.

Isosceles - Two sides with same length.

Scalene - No sides with same length.

Classification based on sides:

Acute-Angled - All angles are acute. (0^{\circ} < \theta < 90^{\circ}, 0^{\circ} < \alpha < 90^{\circ}, 0^{\circ} < \beta < 90^{\circ}, \theta + \alpha + \beta = 180^{\circ})

Right-Angled - One angle is right. (0^{\circ} < \theta < 90^{\circ};\alpha = 90^{\circ}, 0^{\circ} < \beta < 90^{\circ}, \theta + \alpha + \beta = 180^{\circ})

Obtuse-Angled - One angle is obtuse. (0^{\circ} < \theta < 90^{\circ},90^{\circ}

3 0
2 years ago
Store A sells lawnmower fuel for $4.00 per gallon.
LiRa [457]

Answer:

store a- numbers greater than or equal to zero

store b-numbers greater than or equal to zero and integer values only

Step-by-step explanation:

i just tried it i would know

3 0
3 years ago
Help with num 9 please. thanks​
Alik [6]

Answer:

See Below.

Step-by-step explanation:

We want to show that the function:

f(x) = e^x - e^{-x}

Increases for all values of <em>x</em>.

A function is increasing whenever its derivative is positive.

So, find the derivative of our function:

\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]

Differentiate:

\displaystyle f'(x) = e^x - (-e^{-x})

Simplify:

f'(x) = e^x+e^{-x}

Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>

8 0
3 years ago
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