What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
An 80-foot rope is attached to a boat
7 feet above the water level as shown and a
boy jumps over the wake while
wakeboarding. What is the distance between
his hands and the water level?
80 ft
:[?] ft
Round to the nearest hundredth.
enter
Answer:2.81 feet
Answer:
-20n/3n
Step-by-step explanation:
-4 1
--- / ---
9n 15n
Keep, change, flip
- Keep the -4/9n
- Change the division sign to a multiplication sign
- Flip the 1/15n to 15n/1
-4 15n
--- * ---
9n 1
Cross simplify.
9n divided by 3 is 3n.
15n divided by 3 is 5n.
-4 5n
--- * ---
3n 1
-4 times 5n equals -20n
3n times 1 equals 3n
-20n
---
3n
Answer
My answer is in the photo above
The average score of all the students in both classes is 84.
<h3>How to calculate the average?</h3>
The class with 30 students had an average score of 80 on a test. The total score will be:
= 30 × 80
= 2400
A class with 20 students had an average score of 90 on the same test. The total score will be:
= 20 × 90
= 1800
Total scores = 2400 + 1800 = 4200
Number of students = 20 + 30 = 50
The average score will be:
= Total score / Total students
= 4200 / 50
= 84
Learn more about average on:
brainly.com/question/24313700
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