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stellarik [79]
1 year ago
13

OFind the missingangle measures.B.m 41 =9058°A4m 42 =31089Em 3 =o

Mathematics
1 answer:
Anastaziya [24]1 year ago
3 0

step 1

Find the measure of angle 1

REmember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

In the triangle ABC

90+58+<1=180

148+<1=180

<1=180-148

<1=32 degrees

step 2

Find the measure of angle 2

we know that

<2=<1 -----> bt vertical angles

so

<2=32 degrees

step 3

Find the measure of angle 3

REmember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

In the triangle CDE

32+108+<3=180

140+<3=180

<3=180-140

<3=40 degrees

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Derivative of tan(2x+3) using first principle
kodGreya [7K]
f(x)=\tan(2x+3)

The derivative is given by the limit

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

You have

\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}

By this identity, you have

\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}

So in the limit you get

\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}
\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}

The first two limits are both 1, and the single term in the last limit approaches 0 as h\to0, so you're left with

f'(x)=\dfrac12\sec^2(2x+3)

which agrees with the result you get from applying the chain rule.
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3 years ago
Please help me with this question
boyakko [2]

Answer:

0.7999989281

Step-by-step explanation:

x1 = cos^-1 (3/5)

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sin(53.13) = 0.7999989281

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