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1 year ago

Which inequality represebts the graph shown below

Mathematics

1 answer:

GREYUIT [131]1 year ago

6 0

X > -2

The endpoint is a circle so equality is excluded
The arrow points to the right so x is strictly greater than -2

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Rashid [163]

Answer:

T = 5 (H = 7, M = 1); T = 7 (H = 4, M = 2); T = 9 (H = 1, M = 3)

Step-by-step explanation:

We know MH+MH+MH=TM

MH is a two digit number, and TM is also a two digit number.

MH+MH+MH=3*(MH)<100

3M<=9, meaning that M could be 1, 2, or 3.

If M=1, MH+MH+MH=3(10+H)=30+3H=TM=10*T+1

30+3H=10T+1, so 3H must include 1 in one's digit.

The only possibility is that 3H = 21, then H = 7

MH+MH+MH=17+17+17=TM=51, T = 5

If M=2, MH+MH+MH=3(20+H)=60+3H=TM=10T+2

60+3H=10T+2, so 3H must include 2 in one's digit.

The only possibility is 3H = 12, then H = 4

MH+MH+MH=24+24+24=72, T = 7

If M=3, MH+MH+MH=3(30+H)=90+3H=TM=10T+3

90+3H=10T+3, so 3H must include 3 in one's digit.

The only possibility is 3H = 3, then H =1

MH+MH+MH=31+31+31=93, T=9

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3 years ago

GEOMETRY!!!! K' (6,5) is the image of K after a reflection in the line y=2. what are the coordinates of K

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Given:

The coordinates of point K' are (6,5).

K' is the image of K after a reflection in the line y=2.

To find:

The coordinates of point K.

Solution:

Let the coordinates of point K are (a,b).

If a figure is reflected over the line y=2, then

$(x,y)\to (x,2(2)-y)$

$(x,y)\to (x,4-y)$

Using this formula, the coordinates of image of K are

$K(a,b)\to K'(a,4-b)$

The coordinates of point K' are (6,5).

$K'(a,4-b)=K'(6,5)$

On comparing both sides, we get

$a=6\text{ and }4-b=5$

$a=6\text{ and }-b=5-4$

$a=6\text{ and }-b=1$

$a=6\text{ and }b=-1$

Therefore, the coordinates of point K are (6,-1).

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