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Orlov [11]
3 years ago
7

A bus can at most be filled with 36 passengers. If there are

Mathematics
1 answer:
raketka [301]3 years ago
7 0

Answer:

if you subtract 36-25=11 so 11 more passenger can come in the bus

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I'm solving systems and I don't understand how to do it pls helpp
kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

+

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0
2 years ago
Read 2 more answers
3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0
Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

6 0
3 years ago
Read 2 more answers
Help me I want to understand this finnall part
allochka39001 [22]
6.7 x  -2.3
You would multiply this just like any other multiplication question. 
There is some work of course, but I'm not going to write it out here...
You are going to end up with -15.41, which is already rounded to the nearest hundredth.

Hope this helped :)
4 0
3 years ago
Read 2 more answers
What values of b satisfy 4(3b + 2)2 = 64?
Vikentia [17]
Given the equation 4(3b + 2)² = 64, dividing both sides of the equation by 4, we have (3b + 2)² = 16 and getting the square root of both sides, (3b + 2) = 4 and (3b + 2) = -4 We can solve for b for each equation and have 3b = 2 | 3b = -6 b = 2/3 | b = -2 Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>
8 0
3 years ago
Question:
riadik2000 [5.3K]

Answer:

180

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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