Answer:
Option c is right.
Step-by-step explanation:
Given is a parabola y =x^2
From that transformation is done to get parabola as
y =(0.2x)^2
We find that instead of x here we use 0.2x
i.e. New x = 5 times old x
Hence there is a horizontal expansion of scale factor 5.
We can check with any point also
When y =4, x=2 in the parent graph
But when y =4 , we have x = 10 in the new graph
i.e. there is a horizontal expansion of scale factor 5.
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Hello :
cos60 = cos(-60)=0.5
