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solong [7]
1 year ago
5

Help solving this problem, the second problem not the third

Mathematics
1 answer:
yawa3891 [41]1 year ago
7 0

Given:

1 Van and 4 buses filled with 195 students.

1 Van and 5 buses filled with 241 students.

Let x and y be the number of students in Van and number of students in bus.

\begin{gathered} x+4y=195\ldots\text{ (1)} \\ x+5y=241\ldots\text{ (2)} \end{gathered}

Subtract equation (1) from equation (2)

\begin{gathered} x+5y-x-4y=241-195 \\ y=46 \end{gathered}

Substitute y=46 in equation (1)

\begin{gathered} x+4(46)=195 \\ x+184=195 \\ x=195-184 \\ x=11 \end{gathered}

Number of students that van can carry is 11.

Number of students that bus can carry is 46

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<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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Look at the picture part 1
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We need to check the given table.

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Plugging x=-2,-1,0,1,2 in the given equation

For x=-2

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3 years ago
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monitta
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Can anyone help me with this problem ?
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Come now !  I'm sure you could unravel it if you look at it and think about it
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What's an angle bisector ?  It's a line that splits an angle exactly in half.
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So in this drawing,    (3/2 x - 6)    is equal to    (1/4 x + 4) .
Do you think you could find 'x' ?

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Add 6 to each side of the equation:    3/2 x = 1/4 x + 10

Multiply each side by 4 :                     6 x = x + 40

Subtract 'x' from each side:                  5 x = 40

Divide each side by 5 :                          x = 8

Angle  CBD  is  1/4 x + 4 .  That's  1/4 (8) + 4 = 2 + 4 = <u>6 degrees </u>



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