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STatiana [176]
2 years ago
12

Chemistry: need help please and thank you.

Chemistry
1 answer:
andreev551 [17]2 years ago
3 0

Sugar cube dissolve in hot water quickly

Sugar is a white crystalline sweet carbohydrate, a disaccharide, found in many plants and extracted from sugar cane

Here in this experiment add 60ml of cold water in plastic cup then add 60 ml of room temperature water to the another plastic cup and then add hot water in the in the another plastic cup then add sugar cube in this three cup and see in which cup the sugar cube dissolve fastly then in the hot water the sugar dissolve fastly because hot water has more energy than cold water and when water is heated the molecule gain energy and then move faster

Know more about sugar

brainly.com/question/8759549

#SPJ1

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The reaction a(g)⇌2b(g) has an equilibrium constant of k = 0.030. what is the equilibrium constant for the reaction b(g)⇌12a(g)?
aalyn [17]
First, we have to correct the equation in the question to b(g)⇆ 1/2 A(g)
at the first equation A(g)⇆ 2 B(g) so,
 Kc = [B]^2 [ A] = 0.03 

by reverse the equation 2B⇆ A 
∴ Kc(original) = [A] / [B]^2

        = 1/0.03 = 33 M^-1

and the new equation B⇆ (1/2) A 
So, the new Kc = √Kc(original = √33 
                ∴    KC  = 5.7
7 0
4 years ago
Read 2 more answers
During which of the following months is the sun likely to illuminate Earth equally from pole to pole?
Gekata [30.6K]
<span>The sun likely to illuminate Earth equally from pole to pole during March and September.

During these two months, both poles receive the same amount of light. This time is called Equinox. 

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6 0
3 years ago
Need help with this chemistry stoichiometry worksheet any help is appreciated with work shown!
Afina-wow [57]

Answer:

I suggest you study. These can burn up time, so balance the stoichiometry,

Between Oxygen and Propane to yield carbon dioxide.

Aluminum is tricky; Al2O3 is the best choice, especially for the shorter time and what you can learn

Explanation:

5 0
4 years ago
Write balanced equations and Kb expressions for these Brønsted-Lowry bases in water:(CH₃)₃N
grandymaker [24]

(CH3)3N + H2O ---> (CH3)3NH+  +  OH-

The equation of Kb:

Kb = [(CH3)3NH+][OH-]/[(CH3)3N]

<h3>What do we know about the process of dissolution?</h3>

A solute can dissolve in a solvent in a solid, liquid, or gaseous phase to create a solution through the process of dissolution. Solubility. The greatest amount of a solute that may dissolve in a solvent at a particular temperature is known as its solubility. The solution is said to as saturated when the maximum amount of solute is present.

Several variables influence solubility, including:

  • The solute's concentration
  • The system's temperature
  • Pressure (for gases in solution)
  • The solvent's and solute's polarity

To learn more about pKb:

brainly.com/question/14124805

#SPJ4

8 0
2 years ago
1. A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0%
bagirrra123 [75]

Answer:

m_{PbI_2}=18.2gKI

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

2KI+Pb(NO_3)_2\rightarrow 2KNO_3+PbI_2

Thus, we proceed to compute the reacting moles of Pb(NO3)2 and KI, by using the given concentrations and densities and molar masses which are 331.2 g/mol and 166 g/mol respectively:

n_{Pb(NO_3)_2}=96.7mL*\frac{1.134g}{mL}*\frac{0.14gPb(NO_3)_2}{1g}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2}  =0.0464molPb(NO_3)_2\\\\n_{KI}=99.8mL*\frac{1.093g}{mL}*\frac{0.12gKI}{1g}*\frac{1molKI}{166gKI}  =0.0789molKI

Next, the 0.0464 moles of Pb(NO3)2 will consume the following moles of KI (consider their 1:2 molar ratio):

n_{KI}^{consumed\ by\ Pb(NO_3)_2}=0.0464molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0928molKI

Hence, as only 0.0789 moles of KI are available, KI is the limiting reactant, therefore the formed grams of PbI2, considering its molar mass of 461.01 g/mol and 2:1 molar ratio, are:

m_{PbI_2}=0.0789molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gKI

Best regards.

3 0
4 years ago
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