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2 years ago

Write balanced equations and Kb expressions for these Brønsted-Lowry bases in water:(CH₃)₃N

Chemistry

1 answer:

grandymaker [24]2 years ago

8 0

(CH3)3N + H2O ---> (CH3)3NH+ + OH-

The equation of Kb:

Kb = [(CH3)3NH+][OH-]/[(CH3)3N]

<h3>What do we know about the process of dissolution?</h3>

A solute can dissolve in a solvent in a solid, liquid, or gaseous phase to create a solution through the process of dissolution. Solubility. The greatest amount of a solute that may dissolve in a solvent at a particular temperature is known as its solubility. The solution is said to as saturated when the maximum amount of solute is present.

Several variables influence solubility, including:

The solute's concentration
The system's temperature
Pressure (for gases in solution)
The solvent's and solute's polarity

To learn more about pKb:

brainly.com/question/14124805

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Give an example of instantaneous speed

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3 years ago

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A student observes the chemical process described by this equation:

choli [55]

Answer:

Both are equal

Explanation:

Mass of starting material i.e Aluminium is $4.480 * 10^{-23}$ grams

The weight of oxygen is $2.65 * 10^{-23}$

There are 4 atoms of aluminium and 3 atoms of oxygen

Thus, the total mass of starting material is

$4 *$ mass of one atom of aluminium $+ 6 *$ mass of one atom of oxygen

$4 * 4.480 * 10^{-23} + 6* 2.65 * 10^{-23}$

$35.1 * 10^{-23}$ grams

Mass of new substance is also equal to

$4 *$ mass of one atom of aluminium $+ 6 *$ mass of one atom of oxygen

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$35.1 * 10^{-23}$ grams

5 0

3 years ago

Convert the following75 mL to L

Marizza181 [45]

Answer:

0.075 L

Explanation:

7 0

4 years ago

As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the po

Ganezh [65]

Answer:

pH = 2.03

Explanation:

The pH can be calculated using the following equation:

$pH = -log [H_{3}O^{+}]$ (1)

The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:

CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺

1.00 M

$K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}$

Solving the above equation for H₃O⁺, we have:

$[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}$ (2)

The dissociation constant is equal to:

$pKa = -log(Ka) \rightarrow Ka = 10^{-pKa} = 10^{-4.76} = 1.74 \cdot 10^{-5}$

Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:

CH₃COOX ⇄ CH₃COO⁻ + X⁺

5.00x10⁻³ M

$K_{sp} = [CH_{3}COO^{-}][X^{+}]$

$[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M$

By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:

$[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M$

Hence, the pH is:

$pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03$

Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.

I hope it helps you!

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4 years ago

An atom of which element in the ground state contains electrons in the fourth principal energy level?

krok68 [10]

Kr
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3 years ago