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Soloha48 [4]
1 year ago
7

List the angle measures of △VWX in order from smallest to largest. Assume that t is a positive number.

Mathematics
1 answer:
Klio2033 [76]1 year ago
8 0

Explanation

To begin with, we will first have to obtain the length of side VX

VX^2=WX^2+VW^2-2\times WX\times VWcosw

In our case

\begin{gathered} WX=28t \\ VW=95t \\ w=94^0 \end{gathered}

Thus

\begin{gathered} VX^2=(28t)^2+(95t)^2-2\times(28t\times95t)cos94 \\  \\ VX^2=784+9025+371.104 \\ VX^2=100180.10 \\  \\ VX=100.90t \end{gathered}

Next, we will determine the angles at V and X

using sine rule

\begin{gathered} \frac{sin94}{100.9t}=\frac{sinV}{28t} \\  \\ sinV=\frac{28t\times sin94}{100.9t} \\  \\ sinV=0.27683 \\  \\ V=16.07^0 \\  \end{gathered}

Then, we will get the measure at X

180^0-16.07^0-94=69.93^0

Therefore, the order from smallest to largest angles will be

m

OR

m

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