Question

List the angle measures of △VWX in order from smallest to largest. Assume that t is a positive number.

Answer 1

Explanation

To begin with, we will first have to obtain the length of side VX

$VX^2=WX^2+VW^2-2\times WX\times VWcosw$

In our case

$\begin{gathered} WX=28t \\ VW=95t \\ w=94^0 \end{gathered}$

Thus

$\begin{gathered} VX^2=(28t)^2+(95t)^2-2\times(28t\times95t)cos94 \\ \\ VX^2=784+9025+371.104 \\ VX^2=100180.10 \\ \\ VX=100.90t \end{gathered}$

Next, we will determine the angles at V and X

using sine rule

$\begin{gathered} \frac{sin94}{100.9t}=\frac{sinV}{28t} \\ \\ sinV=\frac{28t\times sin94}{100.9t} \\ \\ sinV=0.27683 \\ \\ V=16.07^0 \\ \end{gathered}$

Then, we will get the measure at X

$180^0-16.07^0-94=69.93^0$

Therefore, the order from smallest to largest angles will be

m

OR

m