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4 years ago

12

To the nearest tenth of a degree, ﬁnd the sizes of the acute angles in the 7-24-25 right

1 answer:

fiasKO [112]4 years ago

7 0

First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:

7² + 24² really is 25² , and 8² + 15² really is 17² , so we're OK there.

In the first one:
sin(one acute angle) = 7/25 = 0.28
the angle = sin⁻¹ (0.28) = 16.26°
the other acute angle = (90° - 16.26°) = 73.74°

In the second one:
sin(one acute angle) = 8/17 = 0.4706...
the angle = sin⁻¹ (0.4706...) = 28.07°
the other acute angle = (90° - 28.07°) = 61.93°

I'm sorry, but just now, I don't know how to do the
third triangle in the question.

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vladimir2022 [97]

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