You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Answer:
105
Step-by-step explanation:
15x7
Answer:
square root of 113 or 10.6
Step-by-step explanation:
7^2+ 8^2= C
49+64=C
113=C
square root of 113 OR 10.6
Hope this helped :)
Answer:
Minimum: 
Maximum: 
Step-by-step explanation:
Find the area of each shape first like first the middle square then the triangles and multiply the triangles by 4
