The containers must be spheres of radius = 6.2cm
<h3>
How to minimize the surface area for the containers?</h3>
We know that the shape that minimizes the area for a fixed volume is the sphere.
Here, we want to get spheres of a volume of 1 liter. Where:
1 L = 1000 cm³
And remember that the volume of a sphere of radius R is:
Then we must solve:
![V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2AR%5E3%20%3D%201000cm%5E3%5C%5C%5C%5CR%20%3D%5Csqrt%5B3%5D%7B%20%20%281000cm%5E3%2A%5Cfrac%7B3%7D%7B4%2A3.14%7D%20%29%7D%20%3D%206.2cm)
The containers must be spheres of radius = 6.2cm
If you want to learn more about volume:
brainly.com/question/1972490
#SPJ1
Answer:
7/2 = 35/10
3/5 = 6/10
Step-by-step explanation:
To get a common denominator of 10, simply multiply the current denominator by any number to equal 10. The first fraction has a denominator of 2. If we divide 10 by 2, we get the answer 5. This means 2 can be multiplied by 5 to get a denominator of 10. However, what we do to the denominator we must also do to the numerator (multiply by 5).
7/2
7 × 5 / 2 × 5
35/10
3/5
3 × 2 / 5 × 2
6/10
brainliest pls
i think it’s perpendicular
log_10 (600) is between 2 and 3
2,77815
3(9 - 8x - 4x) + 8(3x + 4) = 11
3(9 - 12x) + 8(3x + 4) = 11
27 - 36x + 24x + 32 = 11
59 - 12x = 11
-12x = 11 - 59
-12x = -48
x = 4
hope this helps, God bless!
