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GenaCL600 [577]
8 months ago
6

PLEASE HELP!! PICTURE INCLUDED!! Please explain how to find angle R!!

Mathematics
1 answer:
mafiozo [28]8 months ago
3 0

Answer:

∠ R = 75°

Step-by-step explanation:

you are correct with answers to a, b, c

d

the sum of the 3 angles in Δ QRS = 180° , that is

∠ Q +∠ R + ∠ S = 180° , so

55° + ∠ R + 50° = 180°

∠ R + 105° = 180° ( subtract 105° from both sides )

∠ R = 75°

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Solve the expression: x = 5, y = 8. x² - 3y =
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Answer:

x^2-3y

5^2-3*8

25-24

1

Step-by-step explanation:

3 0
3 years ago
sean and morgan walked from the same location sean walked 5 1/2 blocks north and 3 1/4 blocks east morgan walked 3 1/4 blocks ea
Yakvenalex [24]

Answer:

10

Step-by-step explanation:

5 1/2  + 4 1/2 = 10

4 0
3 years ago
webassign If a snowball melts so that its surface area decreases at a rate of 6 cm2/min, find the rate at which the diameter dec
drek231 [11]

Answer:

The answer is \frac{3}{10\pi }  cm/min

Step-by-step explanation:

Assuming the snowball is a perfect sphere, then if A denotes the surface area and D the diameter then:

A=4\pi r^{2} = 4\pi (\frac{D}{2} )^{2} =\pi  D^{2}

Differentiating wrt r we have:

\frac{dA}{dD} =2\pi D

We are told that \frac{dA}{dt}= -6 and we want to find \frac{dD}{dt}

By the chain rule we have:

\frac{dA}{dD}=\frac{dA}{dt}.\frac{dt}{dD}=\frac{\frac{dA}{dt} }{\frac{dD}{dt} }

∴2\pi D=-\frac{6}{\frac{dD}{dt} }

∴\frac{dD}{dt}=-\frac{6}{2\pi D}

When D=10 then

\frac{dD}{dt} =-\frac{6}{10*2\pi } =-\frac{3}{10\pi }

The sign (-) shows that the D is decreasing.

3 0
3 years ago
The function f(x) = -5x2 + 13x + 6 represents the height, in meters, of a
AnnZ [28]

Answer:

D

Step-by-step explanation:

Differentiate the function and set it to zero:

f'(x) = -10x + 13

0 = -10x + 13

x = 1.3 seconds

Plug the x value into f(x):

f(1.3) = -5(1.3)^2 + 13(1.3) + 6 = 14.45 meters

8 0
2 years ago
Earth has been charted with vertical and horizontal lines so that points can be named with coordinates. The horizontal lines are
inna [77]
<span>a. The radius of earth is about 6400 kilometers. Find the circumference of a great circle.

Circumference = 2π(radius) = 2π(6400 km) = 40.212,39 km

b. Write an equation for the circumference of any latitude circle with angle theta

As stated, </span><span><span>the length of any parallel of latitude (this is the circumference of corresponding circle) is equal to the circumference of a great circle of Earth times the cosine of the latitude angle</span>:

=> Circumference = 2π*radius* cos(Θ) = 2 π*6400km*cos(Θ) = 40,212.39 cos(Θ)

Answer: circumference = 40,212.39 cos(Θ) km

c. Which latitude circle has a circumference of about 3593 kilometers?

Make </span><span><span>40,212.39 cos(Θ)</span> km = 3593 km

=> cos(Θ) = 3593 / 40,212.39 = 0.08935 => Θ = arccos(0.08935) = 84.5° = 1.48 rad

Answer: 1.48

d. What is the circumference of the Equator? </span>

For the Equator Θ = 0°

=> circumference = 40,213.49cos(0°) km = 40,212.49 km

Answer: 40,212.49 km

7 0
3 years ago
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