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Jet001 [13]
3 years ago
5

From 12 teachers to 48 teachers using percent

Mathematics
1 answer:
Elanso [62]3 years ago
7 0
Given the values above, here is how we are going to solve it using percent. So from 12 teachers to 48 teachers, there are 36 teachers added. Therefore, the percent of increase in this statement is 75%. It is 75% since we based it from the new number of teachers which is 48. Hope this helps.
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(5*10^-2)divide by (2*10^3)
DaniilM [7]

Answer:

2.5 × 10^-5

<em>please correct me if im wrong</em><em>.</em>

6 0
3 years ago
A math professor notices that scores from a recent exam are normally distributed with a mean of 61 and a standard deviation of 8
Alexeev081 [22]

Answer:

a) 25% of the students exam scores fall below 55.6.

b) The minimum score for an A is 84.68.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 61 and a standard deviation of 8.

This means that \mu = 61, \sigma = 8

(a) What score do 25% of the students exam scores fall below?

Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 61}{8}

X - 61 = -0.675*8

X = 55.6

25% of the students exam scores fall below 55.6.

(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?

This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.

Z = \frac{X - \mu}{\sigma}

2.96 = \frac{X - 61}{8}

X - 61 = 2.96*8

X = 84.68

The minimum score for an A is 84.68.

8 0
3 years ago
Plz help math question
Lina20 [59]

Answer:

y = -2x +20

6x - 5y = 12

Put the value of y in 2nd equation

6x - 5( -2x +20 ) = 12

6x +10x -40 = 12

16x = 12 +40

16x = 52

x = 13/4

Putting the value of x in equation 1

y = -2x +20

y = -2(13/4 ) +20

y = 27/2

Do mark me as brainly. THANKS

6 0
2 years ago
the x and y axis are tangent to a circle with radius 3 units. write a standard equation of the circle.
Mekhanik [1.2K]

Given:

The x and y axis are tangent to a circle with radius 3 units.

To find:

The standard form of the circle.

Solution:

It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.

We know that the radius of the circle are perpendicular to the tangent at the point of tangency.

It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Putting h=3,k=3,r=3, we get

(x-3)^2+(y-3)^2=3^2

(x-3)^2+(y-3)^2=9

Therefore, the standard form of the given circle is (x-3)^2+(y-3)^2=9.

3 0
2 years ago
Express your answer in the smaller unit: 231 m 31 cm - 14 m 48 cm
pashok25 [27]
23131-1448 =21683(cm)

6 0
2 years ago
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