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marshall27 [118]
1 year ago
14

Enter numbers to evaluate ‐6−13. ‐6−13= ‐6 + = Enter numbers to evaluate ‐6−(‐13). ‐6−(‐13)= ‐6 + =

Mathematics
1 answer:
Maru [420]1 year ago
7 0

The given expression evaluates to -19.

<h3>What is a expression? What is a mathematical equation? What do you mean by domain and range of a function?</h3>
  • A mathematical expression is made up of terms (constants and variables) separated by mathematical operators.
  • A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
  • For any function y = f(x), Domain is the set of all possible values of [y] that exists for different values of [x]. Range is the set of all values of [x] for which [y] exists.

We have the following expression -

- 6 - 13

The given expression evaluates to -

x = - 6 - 13

x = - 19

Therefore, the given expression evaluates to -19.

To solve more questions on Equations, Equation Modelling and Expressions visit the link below -

brainly.com/question/14441381

SPJ1

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X²-9y²<br>can someone assist plz​
Annette [7]

Answer:

{x}^{2}  - 9 {y}^{2}  \\  =  {x}^{2}  -  {3}^{2}  {y}^{2}  \\  =  {x}^{2}  -  {(3y)}^{2}  \\  = (x - 3y)(x + 3y)

3 0
2 years ago
What is f(x)=14−0.5x? <br><br> solve for f(30)
UkoKoshka [18]
The function f(x) is a function of the variable x.

To solve the function for x = 30, just plug in 30 for x.

14 - 0.5(30) = -1

f(30) = -1
3 0
3 years ago
PLEASE HELP. I'LL GIVE BRAINLIEST.
vova2212 [387]
<h2>Answer:</h2>

The answer is 16.

<h2>Step-by-step explanation:</h2>

Since the 8x is positive, the equation  must have y as a positive number.

Let's see this!

An easy way to complete the square if you have the constants for x2 and

But not the non-variable number is to divide the x constant, and then square it.

Example:

\frac{8x}{2} \\\\4^2=16\\

The last number must be 16. Let's check it.

(x+4)^2=x^2+8x+16

6 0
2 years ago
This is confusing i need help ;-;
katovenus [111]

Answer:

B I think

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4
Goshia [24]

Answer:

\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

Step-by-step explanation:

y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\

\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

6 0
3 years ago
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