A.
![4n-5 = 3n+2](https://tex.z-dn.net/?f=4n-5%20%3D%203n%2B2)
b and c.
add 5 to both sides:
![4n = 3n+7](https://tex.z-dn.net/?f=4n%20%3D%203n%2B7)
subtract 3n from both sides:
B if not then im sorry i tried my best
Answer:
a)
, b)
, c) ![a(1) = 6\,\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%281%29%20%3D%206%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
Step-by-step explanation:
a) The velocity and acceleration function are obtained by deriving the displacement function once and twice, respectively:
![v(t) = 3 \cdot t^{2} - 3\\a(t) = 6 \cdot t](https://tex.z-dn.net/?f=v%28t%29%20%3D%203%20%5Ccdot%20t%5E%7B2%7D%20-%203%5C%5Ca%28t%29%20%3D%206%20%5Ccdot%20t)
b) The acceleration of the particle at such instant is:
![a(3) = 18\,\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%283%29%20%3D%2018%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
c) The time when velocity is zero is:
![3\cdot t^{2} - 3 = 0\\t^{2}-1 = 0\\t^{2}=1\\t = 1](https://tex.z-dn.net/?f=3%5Ccdot%20t%5E%7B2%7D%20-%203%20%3D%200%5C%5Ct%5E%7B2%7D-1%20%3D%200%5C%5Ct%5E%7B2%7D%3D1%5C%5Ct%20%3D%201)
The acceleration is:
![a(1) = 6\,\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%281%29%20%3D%206%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
This is a good answer right here ^
Answer:
<h3>
![\frac{2a}{3a}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2a%7D%7B3a%7D%20)
</h3>
Step-by-step explanation:
![18a ^{2} (c−8)÷27ab(c−8)](https://tex.z-dn.net/?f=18a%20%5E%7B2%7D%20%28c%E2%88%928%29%C3%B727ab%28c%E2%88%928%29)
<h3>
![\frac{18a^{2} (c−8)}{27ab(c−8)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B18a%5E%7B2%7D%20%28c%E2%88%928%29%7D%7B27ab%28c%E2%88%928%29%7D%20)
</h3><h3>
![\frac{2a^{2} (c−8)}{3ab(c−8)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2a%5E%7B2%7D%20%28c%E2%88%928%29%7D%7B3ab%28c%E2%88%928%29%7D%20)
</h3><h3>
![\frac{2a (c−8)}{3ab(c−8)}](https://tex.z-dn.net/?f=%5Cfrac%7B2a%20%28c%E2%88%928%29%7D%7B3ab%28c%E2%88%928%29%7D%20)
</h3><h3>
![\frac{2a}{3a}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2a%7D%7B3a%7D%20)
</h3><h3>Hope it is helpful....</h3>