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kirza4 [7]
3 years ago
7

What does 7526.442 round to the nerest hundredth

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0
7526.44 because you look at the thousanth place (the 2) and since it is less than 5 you round down
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Write an equation of the line, in slope intercept form.
DedPeter [7]

Answer:

y = -3x + 6

Step-by-step explanation:

Slope-intercept form:

y = mx + b

m (slope) = \frac{-6}{2} or -3

b (y-intercept, or where the line crosses the y-axis) = 6

y = -3x + 6

4 0
2 years ago
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Does this graph represent a function? Why or why not?
In-s [12.5K]
B. No, because it fails the vertical line test.
8 0
3 years ago
Please show your work and explain it.
Maru [420]

Answer:

f(x)=\dfrac{x+2}{2(x-2)}

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}

Next we factor what we can so we can further simplify the rest of the equation:

=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\

We can now cancel out (x+2)

=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}

Next we factor out even more:

=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

=\dfrac{(x+2)(1)}{(x-2)(2)}

And we can now simplify it to:

=\dfrac{x+2}{2(x-2)}

6 0
3 years ago
Please help! <br> Simplify. Your answer should contain only positive exponents.
maxonik [38]

Answer:

\frac{1}{4k^3}

Step-by-step explanation:

It's already in a form that only ha positive exponents.  Just to state it though you could rewrite it as k*(4k^{4})^{-1} or k*4^{-1}*k^{-4}  The question asks for positive exponents though so yu don't need to do that.

You also need to know \frac{x^a}{x^b}=x^{a-b} so in this case \frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}

so \frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}

3 0
3 years ago
How many outcome sequences are possible when a die is rolled 4 times where we say for instance that the outcome is 3 4 3 1 if th
STatiana [176]

Answer:

the possible outcome sequences when a die is rolled 4 times is 1296

Step-by-step explanation:

 Given the data in the question;

a die is rolled 4 times

and outcomes are { 3, 4, 3, 1 }

we know that; possible number of outcomes on a die is n = 6{ 1,2,3,4,5,6 }

Now when we roll a die lets say, r times

then the total number of possible outcomes will be;

N = n^r

given that; r = 4

Hence if we roll a die 4 times;

Total number of possible outcome N = 6⁴

N = 1296

Therefore, the possible outcome sequences when a die is rolled 4 times is 1296

3 0
3 years ago
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