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1 year ago

7 . Cans of frozen OJ Total Cost ($) 1.25 1 2 2.50 3 3.75 4 5.00

Mathematics

1 answer:

aliina [53]1 year ago

3 0

$\begin{gathered} x=\text{cans of frozen OJ} \\ f(x)=\text{Total cost(\$)} \\ f(x)=1.25x \\ f(1)=1.25(1)=1.25 \\ f(2)=1.25(2)=2.50 \\ f(3)=1.25(3)=3.75 \\ f(4)=1.25(4)=5.00 \end{gathered}$

Independent variable = x(Cans of frozen OJ)

dependent variable = y(total cost)

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Please Help! Thanks!

svetlana [45]

Answer:

C, 20 units

Step-by-step explanation:

We see that both angles QRS and QTR are 90 degrees. In addition, angles SQR and RQT are equivalent (because they're both angle Q).

By AA Similarity, we know that triangle QTR is similar to triangle QRS.

With this similarity in mind, we can look at the ratios of corresponding lengths to set up a proportion. QR from triangle QTR is the hypotenuse, and it corresponds to hypotenuse QS from triangle QRS. So, we can write the ratio x/(9 + 16) = x/25.

Now, we see that long leg QT of triangle QTR corresponds to long leg QR of triangle QRS. So, another ratio we can write is: 16/x.

Finally, we set these two ratios equal to each other:

$\frac{x}{25} =\frac{16}{x}$

Cross-multiplying, we get: $x^{2} =16*25=400$ .

Thus, x = $\sqrt{400} =20$ . The answer is C, 20 units.

Hope this helps!

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3 years ago

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6 If the altitudes of a triangle meet at one of the triangle’s vertices, then the triangle is

lyudmila [28]

Answer:

1) a right triangle

Step-by-step explanation:

One of the caractheristics of a right triangle, the one in which the sum of the two sides squared is the hypotenuse squared(Pytagorean Theorem), is also the the altitudes of a triangle meet at one of the triangle’s vertices. So 1) is the answer to this question.

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3 years ago

1/4 × -2/3 = how do I solve this problem

Katyanochek1 [597]

$\bf \cfrac{1}{4}\times \cfrac{-2}{3}\implies \cfrac{1\times -2}{4\times 3}\implies \cfrac{-2}{12}\implies \stackrel{simplified}{-\cfrac{1}{6}}$

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3 years ago

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2) WILL MAKE BRAINLIEST <br><br> write the slope-interception form of the equation of each line.

Norma-Jean [14]

Answer:

1.) y= 3

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Step-by-step explanation:

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3 years ago

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi

Dovator [93]

Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?

Answer:

a) mean = 18

Standard deviation =3

b) low range = 12

High range = 24

c) The result of 33 girls is significantly high. Yes, the method is effective.

Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = $\sqrt{npq}$

$= \sqrt{np(1-p)}$

$= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3$

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

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3 years ago