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zhenek [66]
1 year ago
15

on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. what is the velocity (speed and direction)

of the air relative to the runner?
Physics
1 answer:
kiruha [24]1 year ago
4 0

Velocity is the rate of change of position of an object. The velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

<h3>What is Velocity?</h3>

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

Given that on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. Therefore, the velocity of the air relative to the runner can be written as,

Relative velocity = √[(Velocity of the jogger)² + (Velocity of the air)²]

                            = √[(5)² + (5)²]

                            = √(25 + 25)

                            = √50

                            = 5√2 m/sec

The direction of the relative velocity is,

The angle of relative Velocity = Tan(θ)

Tan(θ) = Vertical velocity / Horizontal velocity

Tan(θ) = 5/5

Tan(θ) = 1

θ = tan⁻¹(1)

θ = 45°

Since this angle is formed between the two velocities, therefore, the direction of the velocity is southwest.

Hence, the velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

Learn more about Velocity here:

brainly.com/question/18084516

#SPJ4

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A car is 2.0 km west of a traffic light at t = 0 and 5.0 km east of the light at t = 6.0 min. Assume the origin of the coordinat
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Answer:

(a) Position Vectors V₁= -2î km, V₂=5î km

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Explanation:

Given data

Distance=2 km west at t=0

Distance=5 km east at t=6 min

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To find

(a)Car position vector at given times

(b)Displacement between 0 to 6.0 min

Solution

For Part (a) car position vector at given times

At t=0 the distance=2 km west so conclude that x₁=-2 because it is in negative side So vector V₁

V₁= -2î km

At t=6.0 the distance=5 km east so conclude that x₂=5 because it is in positive side So vector V₂

V₂=5î km

For (b) displacement between 0 to 6.0 min

According to following mathematical law we can conclude that

Δx=x₂-x₁

Δx=5-(-2)km

Δx=7 km

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3 years ago
If y = 0.02 sin (30x – 200t) (SI units), the frequency of the wave is
leva [86]

Answer:

31.831 Hz.

Explanation:

<u>Given:</u>

  • \rm y = 0.02\sin(30x-200 t).

The vertical displacement of a wave is given in generalized form as

\rm y = A\sin(kx -\omega t).

<em>where</em>,

  • A = amplitude of the displacement of the wave.
  • k = wave number of the wave = \dfrac{2\pi }{\lambda}.
  • \lambda = wavelength of the wave.
  • x = horizontal displacement of the wave.
  • \omega = angular frequency of the wave = \rm 2\pi f.
  • f = frequency of the wave.
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On comparing the generalized equation with the given equation of the displacement of the wave, we get,

\rm A=0.02.\\k=30.\\\omega =200.\\

therefore,

\rm 2\pi f=200\\\\\Rightarrow f = \dfrac{200}{2\pi}=31.831\ Hz.

It is the required frequency of the wave.

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-- A tornado follows a path that's a few miles wide, for a few hours.
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Answer:

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As the number of turns will be increased more inevitable losses will be generated that dissipates heat thus warming the primary.

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